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Natali [406]
2 years ago
7

If, at a given temperature, the equilibrium constant for the reaction H2(g) Cl2(g) 2HCl(g) is Kp, then the equilibrium constant

for the reaction HCl(g) (1/2) H2(g) (1/2)Cl2 (g) can be represented as:
Chemistry
1 answer:
ankoles [38]2 years ago
4 0

Answer:

Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

Explanation:

  • H2(g) + Cl2(g) → 2HCl(g)

∴ Kp = F(T)

⇒ Kp = (PHCl/P°)eq / [(PCl2/P°)eq]*[(PH2/P°)eq]

∴ P° = 1 bar

  • HCl(g) → (1/2)H2(g) + (1/2)Cl2(g)

⇒ Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

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For S₂Cl₂, the two sulfurs must be bonded to a simple bond, and each one to one chlorine, thus, for both od them S = 4, and L = 4. so

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2 years ago
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That's all you are asking. Is there more?

5 0
3 years ago
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