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Natali [406]
3 years ago
7

If, at a given temperature, the equilibrium constant for the reaction H2(g) Cl2(g) 2HCl(g) is Kp, then the equilibrium constant

for the reaction HCl(g) (1/2) H2(g) (1/2)Cl2 (g) can be represented as:
Chemistry
1 answer:
ankoles [38]3 years ago
4 0

Answer:

Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

Explanation:

  • H2(g) + Cl2(g) → 2HCl(g)

∴ Kp = F(T)

⇒ Kp = (PHCl/P°)eq / [(PCl2/P°)eq]*[(PH2/P°)eq]

∴ P° = 1 bar

  • HCl(g) → (1/2)H2(g) + (1/2)Cl2(g)

⇒ Kp = [(PH2/P°)∧(1/2)eq]*[(PCl2/P°)∧(1/2)eq] / (PHCl(g)/P°)eq

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The mass of a proton is 1.00728 amu andthat of a neutron is 1.00867 amu. What is the binding energy pernucleon (in J) of a Co nu
andreyandreev [35.5K]

Answer:

The binding energy per nucleon = 1.368*10^-12  (option D)

Explanation:

<u>Step 1:</u> Data given

The mass of a proton is 1.00728 amu

The mass of a neutron is 1.00867 amu

The mass of a cobalt-60 nucleus is59.9338 amu

Step 2: Calculate binding energy

The mass defect = the difference between the mass of a nucleus and the total mass of its constituent particles.

Cobalt60 has 27 protons and 33 neutrons.

The mass of 27 protons = 27*1.00728 u = 27.19656 u

The mass of 33 neutrons = 33*1.00867 u = 33.28611 u

Total mass of protons + neutrons = 27.19656 u + 33.28611 u = 60.48267 u

Mass of a cobalt60 nucleus = 59.9338 amu

Mass defect = Δm = 0.54887 u

ΔE =c²*Δm

ΔE = (3.00 *10^8 m/s)² *(0.54887 amu))*(1.00 g/ 6.02 *10^23 amu)*(1kg/1000g)

Step 3: Calculate binding energy per nucleon

ΔE = 8.21 * 10^-11 J

8.21* 10^-11 J / 59.9338 = 1.368 *10^-12

The binding energy per nucleon = 1.368*10^-12  (option D)

3 0
3 years ago
If you have access to stock solutions of 1.00 M H3PO4, 1.00 M of HCl, and 1.00 M NaOH solution, (and distilled water of course),
garri49 [273]

Answer:

0.10L of 1.00M of H₃PO₄ and 0.1613L of 1.00M NaOH

Explanation:

The pKa's of phosphoric acid are:

H₃PO₄/H₂PO₄⁻ = 2.1

H₂PO₄⁻/HPO₄²⁻ = 7.2

HPO₄²⁻/PO₄³⁻ = 12.0

To make a buffer with pH 9.40 we need to convert all H₃PO₄ to H₂PO₄⁻ and an amount of H₂PO₄⁻ to HPO₄²⁻

To have a 50mM solution of phosphoures we need:

2L * (0.050mol / L) = 0.10 moles of H₃PO₄

0.10 mol * (1L / mol) = 0.10L of 1.00M of H3PO4

To convert the H₃PO₄ to H₂PO₄⁻ and to HPO₄²⁻ must be added NaOH, thus:

H₃PO₄ + NaOH → H₂PO₄⁻ + H₂O + Na⁺

H₂PO₄⁻ + NaOH → HPO₄²⁻ + H₂O + Na⁺

Using H-H equation we can find the amount of NaOH added:

pH = pKa + log [A⁻] / [HA] <em>(1)</em>

<em>Where [A-] is conjugate base, HPO₄²⁻ and [HA] is weak acid, H₂PO₄⁻</em>

<em>pH = 7.40</em>

<em>pKa = 7.20</em>

[A-] + [HA] = 0.10moles <em>(2)</em>

Replacing (2) in (1):

7.40 = 7.20 + log 0.10mol - [HA] / [HA]

0.2 = log 0.10mol - [HA] / [HA]

1.5849 = 0.10mol - [HA] / [HA]

1.5849 [HA] = 0.10mol - [HA]

2.5849[HA] = 0.10mol

[HA] = 0.0387 moles = H₂PO₄⁻ moles

That means moles of HPO₄²⁻ are 0.10mol - 0.0387moles = 0.0613 moles

The moles of NaOH needed to convert all H₃PO₄ in H₂PO₄⁻ are 0.10 moles

And moles needed to obtain 0.0613 moles of HPO₄²⁻ are 0.0613 moles

Total moles of NaOH are 0.1613moles * (1L / 1mol) = 0.1613L of 1.00M NaOH

Then, you need to dilute both solutions to 2.00L with distilled water.

4 0
3 years ago
Which statements are true of a heterozygous mixture ?
Maksim231197 [3]

Answer:

b

Explanation:

2 +4

3 0
3 years ago
Read 2 more answers
Which of the following is the best reference for more information regarding compounding?
stiks02 [169]

Compounding Corner on RxNet is the best reference for more information regarding compounding

<u>Explanation:</u>

RxNet is an open online community, consolidating scientists from the domains of chemistry, biochemistry and expanding industry of drug innovation and improvement. Compounding presents an innovative way for pharmacists to customize prescriptions to suit the requirements of their patients.

The art of compounding employs advanced medicine while still sticking to the roots of the profession of pharmacy. Compounding pharmacies can create unparalleled dosage forms based on patient preferences. Compounded medicines are usually reliable and sufficient for most victims who have spoken to their physician about their wellness.

6 0
3 years ago
A cup of gold colored metal beads was measured to have a mass 425 grams. By water displacement, the volume of the beads was calc
Troyanec [42]

Given parameters;

Mass of gold colored metal beads  = 425g

Volume of water displaced by beads = 48.0cm³

Unknown;

Identity of the metal = ?

Given densities;

Gold: 19.3 g/mL

Copper: 8.86 g/mL

Bronze: 9.87 g/mL

Density is an intensive property of any substance. This implies that we can use the density of any substance to identify it.

Density can be defined as the mass per unit volume of a substance. Every substance has a unique mass per volume.

 Mathematically;

                    Density  = \frac{mass}{volume}

where mass is in kg or g

           volume is in  m³ or cm³

To find the density, we must know the mass and volume.

In this problem, the volume of the gold metal beads is the same as the volume of water displaced. This is a way to measure volume of solids.

Since the volume is given in cm³, and we are comparing with choices that have units in g/mL, we simply convert the volume in cm³ to mL

                   1cm³  = 1mL³

So therefore, volume of gold colored metal is 48mL

Now input the parameters given and solve for the density;

           Density  = \frac{425g}{48mL }    = 8.85g/mL

From the given densities, we clearly see that copper is the metal since they both of similar densities.

4 0
3 years ago
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