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Alisiya [41]
3 years ago
11

Jennifer buys school supplies for $12.16. The sales tax is 7.25% what is the amount of tax for Jennifer’s purchases? Show how yo

u solved the problem.
Mathematics
2 answers:
victus00 [196]3 years ago
8 0

Answer:   $ 0.88

Step-by-step explanation:

Given : Jennifer buys school supplies for $12.16.

i.e. Total sales = $12.16

The sales tax = 7.25%  = 0.0725 [We divide percent by 100 to convert it into decimal]

Then , the amount of tax for Jennifer’s purchases=  (Sales tax) x (Total sales)

= (0.0725) x ($12.16)

= $0.8816≈ $ 0.88  [Round off to the nearest cent]

Hence, the amount of tax for Jennifer’s purchases is  $ 0.88.

11111nata11111 [884]3 years ago
7 0

Answer:

$12.16 x .0725 = .8816 round is .88 cents

Step-by-step explanation:

change % to decimal and multiply

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18 3/4 cups are required to bake 15 dozen of cookies.

Step-by-step explanation:

x = 75/4

x = 18 3/4 cups

18 3/4 cups are required to bake 15 dozen of cookies.

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Solve the equation<br> 6.7x = 5.2x + 12.3
Anna [14]

Answer:

x = 8.2

Step-by-step explanation:

6.7x = 5.2x + 12.3

6.7x - 5.2x = 12.3

1.5x = 12.3

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7 0
3 years ago
The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
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