A series circuit has a current of 2 Amperes and an equivalent resistance of 4 Ohms. What is the power of this circuit?
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Based on my information, this would actually be representing "the average kinetic energy of water particles". So, as you take notice that where this temperature is being located, and also, how this would be 
°C, this would make more sense for this to be representing as <span>the average kinetic energy of water particles.</span>
When a satellite is moving around the Earth's orbit, two equal forces are acting on it. The centripetal and the centrifugal force. The centripetal force is the force that attracts the object toward the center of the axis of rotation. The opposite force is the centrifugal force. It draws the object away from the center. When these forces are equal, the satellite uniformly rotates along the orbit.
Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration
ω^2r
where
= mass of earth
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>
= radius of earth
ω = angular velocity
<span>r = radius of orbit
To convert to angular velocity:
</span>Tangential velocity = rω
ω = 5000/r
Then,
r = 2557110.465 m
Therefore, the distance of the centers of the earth and the satellite is 2.6 x 10^6 m.
<span>
</span>
Centripetal force = Centrifugal force
Mass of satellite * centripetal acceleration = Mass of satellite * centrifugal acceleration
Centripetal acceleration = Centrifugal acceleration
where
G = gravitational constant = 6.6742 x 10-11<span> m</span>3<span> s</span>-2<span> kg</span><span>-1
</span>
ω = angular velocity
<span>r = radius of orbit
To convert to angular velocity:
</span>Tangential velocity = rω
ω = 5000/r
Then,
r = 2557110.465 m
Therefore, the distance of the centers of the earth and the satellite is 2.6 x 10^6 m.
<span>
</span>