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3 years ago

How many photons with 10 ev are required to produce 20 joules of energy?

1 answer:

6 0

One electron Volt (eV) is equal to 1.6 x 10^-19 Joules. Therefore, 10 eV is equal to 1.6 x 10^-18 Joules. In order to produce 20 Joules of energy from 10 eV photons, we would require 20 x 1/(1.6 x 10^-18) = 1.25 x 10^19 particles. This demonstrates that in the world of particle physics, the Joule is a massive energy unit relative to the commonly used electron Volt.

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Bob is coming toward you at a speed of 75 km/hr. You throw a baseball in his direction at 75 km/hr. What does he see the ball do

KengaRu [80]

Answer:

He sees the ball coming at him at 150 km/hr.

Explanation:

In Newtonian physics, the observer would say that the velocity of the first object is the sum of the two velocities.

Due to the same direction, both velocities will be added.

4 0

3 years ago

Read 2 more answers

1. Two-point charges, QA = +8 μC and QB = -5 μC, are separated by a distance r = 10 cm. What is the magnitude and direction of t

densk [106]

Answer:

F = 36 N

Explanation:

Given that,

Charge, q₁ = +8 μC

Charge, q₂ = -5 μC

The distance between the charges, r = 10 cm = 0.1 m

We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :

$F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times8\times 10^{-6}\times 5\times 10^{-6}}{(0.1)^2}\\F=36\ N$

So, the magnitude of the electrostatic force is 36 N.

3 0

2 years ago

Explain how the global sea surface temperature is affected by solar activity.

Dahasolnce [82]

The higher the solar activity, and the hotter it is, the more the oceans heat up and water evaporates into the atmosphere. High amounts of water vapor causes things like hurricanes. However, oceans have a high absorption rate of heat so they can absorb a lot of it without heating up the atmosphere, which is pretty good or else the Earth would overheat.

8 0

2 years ago

Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'

uranmaximum [27]

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.174 ft/s²

Equation of motion

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s$

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-182.218^2}{2\times 3.6}\\\Rightarrow a=-4611.58\ ft/s^2$

Magnitude of acceleration while stopping is 4611.58 ft/s²

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2 years ago

Which of the following will result in learning violent behavior through observational learning?

vovikov84 [41]

What are the choices?

5 0

3 years ago