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Ilya [14]
3 years ago
11

How many photons with 10 ev are required to produce 20 joules of energy?

Physics
1 answer:
oee [108]3 years ago
6 0
One electron Volt (eV) is equal to 1.6 x 10^-19 Joules. Therefore, 10 eV is equal to 1.6 x 10^-18 Joules. In order to produce 20 Joules of energy from 10 eV photons, we would require 20 x 1/(1.6  x 10^-18) = 1.25 x 10^19 particles. This demonstrates that in the world of particle physics, the Joule is a massive energy unit relative to the commonly used electron Volt. 
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slader A girl of mass 55 kg throws a ball of mass 0.80 kg against a wall. The ball strikes the wall horizontally with a speed of
Ivan

Answer: 800N

Explanation:

Given :

Mass of ball =0.8kg

Contact time = 0.05 sec

Final velocity = initial velocity = 25m/s

Magnitude of the average force exerted on the wall by the ball is can be calculated using the relation;

Force(F) = mass(m) * average acceleration(a)

a= (initial velocity(u) + final velocity(v))/t

m = 0.8kg

u = v = 25m/s

t = contact time of the ball = 0.05s

Therefore,

a = (25 + 25) ÷ 0.05 = 1000m/s^2

Therefore,

Magnitude of average force (F)

F=ma

m = mass of ball = 0.8

a = 1000m/s^2

F = 0.8 * 1000

F = 800N

6 0
3 years ago
What is the λ (in m) of an electromagnetic wave that has a frequency of 5.68 x 107 Hz? Enter a numerical response in 3 significa
denpristay [2]

Answer:

Wavelength of electromagnetic wave will be 5.281 m

Explanation:

We have given frequency of electromagnetic wave is f=5.68\times 10^7Hz

Velocity of electromagnetic wave is c=3\times 10^8m/sec

We have to fond the wavelength of the electromagnetic wave

We know that velocity of electromagnetic eave is given by v=\lambda f, here \lambda is wavelength and f is frequency

So \lambda =\frac{v}{f}=\frac{3\times 10^8}{5.68\times 10^7}=5.281m

Wavelength of electromagnetic wave will be 5.281 m

6 0
3 years ago
Individuals who smoke will have a higher frequency of developing cancer later in life.
ivanzaharov [21]
True


idk what you're asking
5 0
2 years ago
A 1200 kg car is travelling qt 20m\s determine the work that must be done on the car by the frictional force of the brakes to st
Anestetic [448]

Answer:

240000 Joules

Explanation:

Applying,

The work that must be done by the frictional force of the brake to stop the car must be equal to the kinetic energy of the car.

W = mv²/2.................. Equation 1

Where W = work done by the frictional force of the brake, m = mass of the car, v = velocity of the car.

From the question,

Given: m = 1200 kg, v = 20 m/s

Substitute these values into equation 1

W = (1200×20²)/2

W = 240000 Joules

4 0
2 years ago
Which graph shows the correct relationship between kinetic energy and speed?
AlexFokin [52]
Show the graph. I need to see the graph first in order to get the awnser
3 0
3 years ago
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