Answer:
B----->2 upper C l plus 2 e superscript minus right arrow 2 upper C l superscript minus.
Explanation:
I took the test and checked the answers, this is for edg2020
Such ions are said to be isoelectronic
H₂:
M=2g/mol
m=10g
n = m/M = 10g/2g/mol = 5mol
O₂:
M = 32g/mol
m = 80g
n = m/M = 80g/32g/mol = 2,5mol
2H₂ + O₂ ⇒ 2H₂O
2mol : 1mol : 2mol
5mol : 2,5mol : 5mol
10g : 80g : 10g+80g=90g
B
When there are lone pairs on the valence shell of the central atom in a molecule, the bond angle is decreased.
The shape of molecules depend on the number of electron pairs on the valence shell of the molecules. These electron pairs could be lone pairs or bond pairs. Lone pairs occupy more space around the central atom since it is attracted to only one nucleus compared to bond pairs which are attracted to two nuclei.
When lone pairs are present on the central atom in a molecule, they tend to "squeeze" the molecule thereby decreasing the bond angle in the molecule. Hence, presence of one or more lone pairs of electrons make the bond angles get smaller.
Learn more: brainly.com/question/10079361
Answer:
The answer would be C. The reason being they're in different groups on the periodic table, so different reactivity.
