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RUDIKE [14]
3 years ago
15

Which of the following representations shows how one variable changes in response to another variable?

Chemistry
2 answers:
marysya [2.9K]3 years ago
7 0

Answer:

The correct answer is B. Line Graphs

Explanation:

likoan [24]3 years ago
6 0
Its B!!!! hope this helps
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What is the density of an object with a mass of 40.0 g and a volume of 80.0 cm3
Komok [63]
Density = mass/volume
D  = 40/80 = 0.5g
D= 0.5g
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What is GMOs? ( Thanks btw )​
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Answer:

living organisms whose genetic material has been artificially manipulated in a laboratory through genetic engineering

Explanation:

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2 years ago
The useful metal manganese can be extracted from the mineral rhodochrosite by a two-step process.... In the first step, manganes
frez [133]

Answer : The mass of MnCO_3 required are, 35 kg

Explanation :

First we have to calculate the mass of MnO_2.

The first step balanced chemical reaction is:

2MnCO_3+O_2\rightarrow 2MnO_2+2CO_2

Molar mass of MnCO_3 = 115 g/mole

Molar mass of MnO_2 = 87 g/mole

Let the mass of MnCO_3 be, 'x' grams.

From the balanced reaction, we conclude that

As, (2\times 115)g of MnCO_3 react to give (2\times 87)g of MnO_2

So, xg of MnCO_3 react to give \frac{(2\times 87)g}{(2\times 115)g}\times x=0.757xg of MnO_2

And as we are given that the yield produced from the first step is, 65 % that means,

60\% \text{ of }0.757xg=\frac{60}{100}\times 0.757x=0.4542xg

The mass of MnO_2 obtained = 0.4542x g

Now we have to calculate the mass of Mn.

The second step balanced chemical reaction is:

3MnO_2+4Al\rightarrow 3Mn+2Al_2O_3

Molar mass of MnO_2 = 87 g/mole

Molar mass of Mn = 55 g/mole

From the balanced reaction, we conclude that

As, (3\times 87)g of MnO_2 react to give (3\times 55)g of Mn

So, 0.4542xg of MnO_2 react to give \frac{(3\times 55)g}{(3\times 87)g}\times 0.4542x=0.287xg of Mn

And as we are given that the yield produced from the second step is, 80 % that means,

80\% \text{ of }0.287xg=\frac{80}{100}\times 0.287x=0.2296xg

The mass of Mn obtained = 0.2296x g

The given mass of Mn = 8.0 kg = 8000 g     (1 kg = 1000 g)

So, 0.2296x = 8000

x = 34843.20 g = 34.84 kg = 35 kg

Therefore, the mass of MnCO_3 required are, 35 kg

4 0
3 years ago
Read 2 more answers
When is an atom least likely to react
KonstantinChe [14]
When the atom is stable
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2 years ago
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Convert 1.75 g/mL to the unit g/m3. Answer Choices: (1.75 x 106 g/m3), (1.75 x 102 g/m3), (1.75 x 10-2 g/m3), (1.75 x 10-6 g/m3)
Marta_Voda [28]
 Answer : 1750000g/cm3
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