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DanielleElmas [232]
2 years ago
13

Please help, please don’t answer links

Chemistry
1 answer:
lakkis [162]2 years ago
3 0

Answer:

0.093 mole of C₆H₁₂.

Explanation:

We'll begin by calculating the molar mass of C₆H₁₂. This can be obtained as follow:

Molar mass of C₆H₁₂ = (12×6) + (12×1)

= 72 + 12

= 84 g/mol

Finally, we shall determine the number of mole in 7.8 g of C₆H₁₂. This can be obtained as follow:

Molar mass of C₆H₁₂ = 84 g/mol

Mass of C₆H₁₂ = 7.8 g

Mole of C₆H₁₂ =?

Mole = mass / molar mass

Mole of C₆H₁₂ = 7.8 / 84

Mole of C₆H₁₂ = 0.093 mole

Thus, 7.8 g contains 0.093 mole of C₆H₁₂.

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b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)].

The generalized Pitzer correlation is :

T_c = 647.1 \ K \\ \\ P_c = 22055 \  kPa  \\ \\ \omega = 0.345

T__{\gamma}} = \frac{T}{T_c}

T__{\gamma}} = \frac{523.15}{647.1}

T__{\gamma}} = 0.808

P__{\gamma}} = \frac{P}{P_c}

P__{\gamma}} = \frac{1800}{22055}

P__{\gamma}} = 0.0816

B_o = 0.083 - \frac{0.422}{T__{\gamma}}^{1.6}}

B_o = 0.083 - \frac{0.422}{0.808^{1.6}}

B_o = 0.51

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B_1 = -0.282

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Z = 1+ (B_o + \omega B_1 ) \frac{P__{\gamma}}{T__{\gamma}}

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