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4 years ago

A wheel rotates 3 times. What is its angular displacement?

Physics

2 answers:

tia_tia [17]4 years ago

5 0

Answer:

The angular displacement would be 6 Pi radians or 1080 degrees.

Explanation:

Every individual rotation is 2 Pi (this applies to anything regardless of radius).

Since there are three rotations you are going to multiply 2 Pi by 3.

This will give you 6 Pi which you can convert to equal 1080 degrees (1 Pi = 180 degrees).

coldgirl [10]4 years ago

3 0

The wheel has rotated through an angular distance of 6π radians, or 1,080 degrees.

Its angular displacement is zero, because its initial and final positions are the same ... there's zero angle between them.

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Read 2 more answers

A lowly high diver pushes off horizontally with a speed of 2.00 m/s from the platform edge 10.0 m above the surface of the water

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(a) 1.6m

(b) 6.86m

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This is a horizontal shooting problem, so we will use the following equations.

For horizontal distance x we use:

$x(t)=x_{0}+v_{0}t$

Where $x(t)$ is the horizontal distance at a time $t$ , $x_{0}$ is the initial horizontal position which in this case will be zero: $x_{0}=0$ . And $v_{0}$ is the initial speed: $v_{0}=2m/s$

So to solve (a):

(a) At what horizontal distance from the edge is the diver 0.800 s after pushing off?

we have that the time is: $t=0.8s$ so the horizontal distance is:

$x(0.8)=(2m/s)(0.8s)1.6m$

The answer for (a) is 1.6m

Now, to solve (b) we need the equation for vertical distance:

$y(t)=y_{0}-\frac{1}{2}gt^2$

Where $y(t)$ is the vertical distance at a time $t$ , $y_{0}$ is the initial vertical distance: $y_{0}=10m$ And $g$ is the gravitational acceleration: $g=9.81m/s^2$ }