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3 years ago

A solution of ammonia NH3(aq) is at equilibrium. How would the equilibrium

Chemistry

1 answer:

Dmitriy789 [7]3 years ago

7 0

Answer:

If NH4+ is removed, the reaction will shift toward products to replace the product removed. This means the reaction will shift to the right.

Explanation:

A solution of ammonia NH3(aq) can be written through the following equation:

NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

If the concentration of one of the reactants changes, the balance will shift in such a way that the change in concentration is counteracted.

If NH4+ is removed, now there is less product, so the reaction will shift toward products to replace the product removed. This means the reaction will shift to the right.

This principle is due to the fact that the equilibrium constant for this reaction is constant at a certain temperature. The ratio of reactants and products is fixed. Any change in concentration disrupts the balance and will result in the balance being restored.

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Which location represents a period on a Periodic Table? A. a vertical row B. a horizontal row C. a diagonal row on the per

prohojiy [21]

The periods inside the Periodic Table is B. a horizontal row, and is numbered 1 through 7

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3 years ago

Formula of preparation of sodium hydroxide

Umnica [9.8K]

The chemical formula of sodium hydroxide is NaOH, and its molar mass is 40.01 g/mol. It is the alkali salt of sodium, and its structure is shown below:

It is an ionic compound consisting of sodium cation (Na+) and hydroxide (OH-) anion.

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3 years ago

How many total orbitals are within the 3s 3p, and 3d sublevels of the third

vredina [299]

Answer: C

Explanation:

The one closest to the atomic center, there is a single 1s orbital that can hold 2 electrons. At the next energy level, there are four orbitals.

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3 years ago

Read 2 more answers

A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid

Len [333]

The molar mass of the acid if 28. 5 ml of the koh solution is required to neutralize the sample is 90.23g/mol.

<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

Given,

Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

Moles = (0.18× 28.5)/1000

= 0.00513 mol

<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

Given,

Mass of HA = 0.462 g

Moles of HA = 0.00512 mol

0.00512 = 0.462/ Molar mass

Molar mass = 90.23 g/ mol.

Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

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1 year ago

How many moles of Cu(OH)2 are soluble in 1L of sodium hydroxide (NaOH) when the pH is 8.23?

Morgarella [4.7K]

Answer:

4.96E-8 moles of Cu(OH)2

Explanation:

Kps es the constant referring to how much a substance can be dissolved in water. Using Kps, it is possible to know the concentration of weak electrolytes. Then, pKps is the minus logarithm of Kps.

Now, we know that sodium hydroxide (NaOH) is a strong electrolyte, who is completely dissolved in water. Therefore the pH depends only on OH concentration originating from NaOH. Let us to figure out how much is that OH concentration.

$pH= -log[H]\\pH= -log (\frac{kw}{[OH]})$