Answer:
A) increasing the pressure
Explanation:
Given the exothermic reaction:
2SO₂(g) + O₂(g) ↔ 2SO₃(g)
the question asks what will make the number of moles of SO₃(g) to increase.
When an equilibrium is disturbed, the system will shift in order to counteract the change (see <em>Le Chatelier's Principle</em>) So <em>when the pressure is increased in a reaction involving gases, the equilibrium will shift trying to decrease the number of moles </em>(because pressure is produced by molecules hitting the container), that is in this case it will shift towards the right side, towards the production of SO₃, thus increasing the number of moles of SO₃.
The number of moles in the right side is 2 and the number of moles in the left side is 3.
Answer:
16.8%
Explanation:
31% NaOH molar mass 40 gm
69% H2O molar mass 18 gm
1000 gm would be
310 gm NaOH or 310/40 = 7.75 moles
690 gm of H2O or 690/18 = 38.333 moles
7.75 / (7.75 + 38.333) = .168 mole fraction
39.96 g product form when 16.7 g of calcium metal completely reacts.
<h3>What is the stoichiometric process?</h3>
Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.
Equation:
→ 
In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:
= 16.7 g Ca x 
x 
x 
= 39.96 g
Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.
Learn more about the stoichiometric process here:
brainly.com/question/15047541
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<span>Because mona means 1 atom, and a compound is made up of 2 or more atoms.</span>
