Answer:
min-mid-max-mid-min
-cosine
Step-by-step explanation:
This is the correct answer, further proof in the file attached.
Factor out -4
-4(x^3+3x^2-2x-6
Factor out x^2
-4(x^2(x+3)-2x-6)
Factor out -2
-4(x^2(x+3)-2(x+3))
Factor out x+3
-4(x+3)(x^2-2)
Answer:
B
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
Here [ a, b ] = [ - 1, 6 ] and from the graph
f(b) = f(6) = 0
f(a) = f(- 1) = 0, thus
average rate of change = = = 0
Answer:All coordinate pairs that are in Quadrant I will have a positive x value and a positive y value. All coordinate pairs that are in Quadrant II will have a negative x value and a positive y value. All coordinate pairs that are in Quadrant III will have a negative x value and a negative y value.
Step-by-step explanation:ebob
81.42
= 81+ 0.42
= 81+ 42/100
= 81+ (42/2) / (100/2)
= 81+ 21/50
= 81 21/50
The final answer is 81 21/50~