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ValentinkaMS [17]
3 years ago
14

An instrument that allows you to look closely at objects that are invisible to the human eye, including cells

Chemistry
1 answer:
xxMikexx [17]3 years ago
4 0
The answer is Microscope
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Einstein used the photoelectric effect to prove that light has what?
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Einstein used the photoelectric effect to show that light can behave both as a particle and as a wave.
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What are the advantages of using a computer over a graphing calculator
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The advantages of using a computer over a graphing calculator is the the "Computer larger amount of data" then the graphing calculator 

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5 0
3 years ago
A chemical reaction in which one element replaces another element in a compound can be categorized as?
alexira [117]
Replacement reaction
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3 years ago
What is the molarity of a solution that contains 87.75g of NaCI in 500.ml of solution
Brut [27]

Answer:

M = 3.0 mol/L.

Explanation:

  • We can calculate the molarity of a solution using the relation:

<em>M = (mass x 1000) / (molar mass x V)</em>

  • M is the molarity "number of moles of solute per 1.0 L of the solution.
  • mass is the mass of the solute (g) (m = 87.75 g of NaCl).
  • molar mass of NaCl = 58.44 g/mol.
  • V is the volume of the solution (ml) (V = 500.0 ml).

∴ M = (mass x 1000) / (molar mass x V) = (87.75 g x 1000) / (58.44 g/mol x 500.0 ml) = 3.0 mol/L.

6 0
3 years ago
A compound is 52.0% zinc 9.6% carbon and 38.4% oxygen. Calculate the empirical formula of the compound.
skad [1K]

Answer:

So a compound is 52% Zinc(Zn), 9.6% Carbon(C), and 38.4% Oxygen (O). Let’s first start off by assuming that we have 100 g of this compound. This means that we have 52 g of Zinc, 9.6 g of Carbon, and 38.4 g of Oxygen.Zinc = 65.38 g/molCarbon = 12 g/molOxygen = 16 g/molThis means we have:52 g of Zn(1 mol Zn/65.38 g of Zn) ≈0.8 mol of Zn.9.6 g of C(1 mol C/12 g of C) = 0.8 mol of C38.4 g of O(1 mol of O/16 g of O) = 2.4 mol of O.

Explanation:

What we want to do next is divide each element by the common factor of all of them, which is 0.8. In most cases, you divide each element by the element with the least amount of moles. After we divide each by 0.8, you’ll notice you have 1 Zn, 1 C, and 3 O. This gives you the empirical formula of ZnCO3, or Zinc Carbonate.

6 0
2 years ago
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