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3 years ago

* Use the periodic table

Chemistry

2 answers:

rodikova [14]3 years ago

6 0

160. you use a mole over grams ratio. 5.0x32mass of O2)

balandron [24]3 years ago

6 0

160 maybe is the correct answer

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The combustion of ethane (C2H6) produces carbon dioxide and steam. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) How many moles of CO2 are pro

Gwar [14]

Answer: 11.2 moles of $CO_2$ are produced when 5.60 mol of ethane is burned in an excess of oxygen.

Explanation:

The combustion of ethane is represented using balanced chemical equation:

$2C_2H_6(g)+7O_2(g)\rightarrow 4CO_2(g)+6H_2O(g)$

As oxygen is preset in excess, ethane acts as the limiting reagent as it limits the formation of product.

According to stoichiometry :

2 moles of propane produces 4 moles of carbon dioxide

Thus 5.60 moles of propane will produce= $\frac{4}{2}\times 5.60=11.2$ moles of carbon dioxide

Thus 11.2 moles of $CO_2$ are produced when 5.60 mol of ethane is burned in an excess of oxygen.

6 0

3 years ago

How can the Swartz process be modified to work for bacteria? Explain.

scZoUnD [109]

Answer:

https://swartzbiotechnologylab.sites.stanford.edu/research

Explanation:

7 0

3 years ago

This sketch of a neutral molecule is shaded red or blue wherever the electrostatic potential at the molecule's surface isn't zer

Natalka [10]

The electrostatic potential is the work done to remove the charge. The molecule showing the potential map shows that it is HI.

<h3>What is electronegativity?</h3>

Electronegativity is the elemental property to attract the electron toward the atom and is affected by atomic number and the atomic radius. The map shows that the molecule is made of two different atoms and has linear geometry.

Due to the linear geometry, the molecule cannot be Br₂ and SO₃ as they are nonpolar and nonlinear respectively. Similarly, BrF and ICl can be eliminated as they are interhalogen compounds. In the HI molecule, the hydrogen atom is a cation and the iodine atom is an anion that has high electronegativity differences.

Therefore, HI is the molecule depicted in the potential map.

Learn more about the electrostatic potential here:

brainly.com/question/14889552

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8 0

3 years ago

One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K

mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy ( $s_{2} - s_{1}$ ), in joules per gram-Kelvin, by the following model:

$s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }$

$s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}}$ (1)

Where:

$m$ - Mass, in kilograms.

$c_{w}$ - Specific heat of water, in joules per kilogram-Kelvin.

$T_{1}$ , $T_{2}$ - Initial and final temperatures of water, in Kelvin.

If we know that $m = 1\,kg$ , $c_{w} = 4190\,\frac{J}{kg\cdot K}$ , $T_{1} = 373.15\,K$ and $T_{2} = 288.15\,K$ , then the change in entropy for the entire process is: