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suter [353]
2 years ago
13

Please answer all.... it’s for chemistry

Chemistry
1 answer:
zvonat [6]2 years ago
7 0
1.)<span>1.5 atm= 1140mm Hg
2.)190mm Hg= .25 atm
3.)253mm Hg= 0.332895 atm
4.).2 atm =152mm Hg
5.)1.5mm Hg= 0.199984 kPa
6.)190mm Hg= 25.3313 kPa
7.)103.2 kPa= 774.06355mm Hg
8.)153mm Hg= 20.3983 kPa
9.)99.8 kPa= </span>0.9849494 atm
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Consider the data presented below. time (s) 0 40 80 120 160 moles of a 0.100 0.067 0.045 0.030 0.020 part a part complete determ
Whitepunk [10]
To determine which order of the reaction it is, first we need to calculate the rate of change of moles.
the data is as follows 
time         0         40        80       120       160
moles    0.100   0.067  0.045    0.030    0.020


Q1)
for the first 40 s change of moles ;
      = -d[A] / t
      = - (0.067-0.100)/40s
      = 8.25 x 10⁻⁴ mol/s
for the next 40 s
      = -(0.045-0.067)/40
      = 5.5 x 10⁻⁴ mol/s
the 40 s after that
      = -(0.030-0.045)/40 s 
     = 3.75 x 10⁻⁴ mol/s
k - rate constant
and A is the only reactant that affects the rate of the reaction

rate = k [A]ᵇ
8.25 × 10⁻⁴ mol/s = k [0.100 mol]ᵇ ----1
5.5 x 10⁻⁴ mol/s = k [0.067 mol]ᵇ   -----2
divide the 2nd equation by the 1st equation
1.5 = [1.49]ᵇ
b is almost equal to 1
Therefore this is a first order reaction

Q2)
to find out the rate constant(k), we have to first state the equation for a first order reaction.
rate = k[A]ᵇ
As A is the only reactant thats considered for the rate equation. 
Since this is a first order reaction,
b = 1
therefore the reaction is 
rate = k[A]
substituting the values,
8.25 x 10⁻⁴ mol/s = k [0.100 mol]
k = 8.25 x 10⁻⁴ mol/s /0.100mol
   = 8.25 x 10⁻³ s⁻¹

7 0
3 years ago
What is the maximum number of moles of N-acetyl-p-toluidine can be prepared from 70. milliliters of 0.167 M p-toluidine hydrochl
Kitty [74]

Answer:

\large \boxed{\text{0.012 mol}}  

Explanation:

We will need a balanced equation with moles, so let's gather all the information in one place.

               CH₃C₆H₄NH₂·HCl + (CH₃CO)₂O ⟶ CH₃C₆H₄NHCOCH₃ + junk

V/mL:                    70.

c/mol·L⁻¹:             0.167

For simplicity in writing , let's call p-toluidine hydrochloride A and N-acetyl-<em>p</em>-toluidine B.

The equation is then

A + Ac₂O ⟶ B + junk

1. Moles of A

\text{Moles of A} = \text{70. mL A}\times \dfrac{\text{0.167 mmol A}}{\text{1 mL A}}= \text{12 mmol A}

2. Moles of B

The molar ratio is 1 mol B:1 mol A

Moles of B = moles of A = 12 mmol = 0.012 mol

\text{You can prepare $\large \boxed{\textbf{0.012 mol}}$ of N-acetyl-p-toluidine. }

3 0
2 years ago
Plss help me pass . I am so confused in chemistry !!
Lapatulllka [165]

Answer:

Explanation:

Ok so an atom is each ball. So in the first one there are 5 balls. In the second one there are 4 and so on. A molecule contains more than two balls. So they are all molecules. For the counting reactants and products, count how many balls are to the left of the arrow which is your number of reactants and count the balls to the right to find the number of product atoms.

3 0
3 years ago
True or Fase. Every substance has to be classified as either acid or base?
Sever21 [200]

Answer:

False

Explanation:

Some substances don't have to be

8 0
2 years ago
What is the molar mass of Agl2​
Maru [420]

Answer:

107.8682

Explanation:

....................

7 0
3 years ago
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