Answer:
7.5 moles of O₂.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2KClO₃ —> 2KCl + 3O₂
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Finally, we shall determine the number of mole of O₂ produced by the decomposition of 5 moles of KClO₃. This can be obtained as follow:
From the balanced equation above,
2 moles of KClO₃ decomposed to produce 3 moles of O₂.
Therefore, 5 moles of KClO₃ will decompose to produce = (5 × 3)/ 2 = 7.5 moles of O₂.
Thus, 7.5 moles of O₂ were obtained from the reaction.
Solids- wood, sand, brick, rock
Liquids- water, milk, blood, coffee
Gases- air, helium, nitrogen, hydrogen
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Mole is the unit of amount of substances of specified elementary entities
According to the ideal gas law he number of moles of a gas n can be calculated knowing the partial pressure of a gas p in a container with a volume V at an absolute temperature T from the equation
n =pV/RT
Here given data is volume = 87.1 liters
Temperature = 74 °C means 347.15 k
Pressure = 3.5 atm
R = 0.0821
Putting this value in ideal gas equation then
n =pV/RT
n = 3.5 atm×87.1 liters / 0.0821 ×347.15 k
n = 021.65 mole
Moles of helium is required to blow up a balloon to 87.1 liters at 74 C and 3.5 atm is 021.65 mole
Know more about mole of helium
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False pollen<span> is transported to nearby </span>plants<span> by raindrops. ... embryo sac of angiosperms </span>consists of<span> eight diploid cells and one haploid egg cell</span>
Answer:
The answer to your question is: 25 g of PbCl2
Explanation:
Data
NaCl = 25 g
PbCl₂ = ?
Pb(NO3)2 + 2 NaCl ⇒ PbCl2 + NaNO3
MW NaCl = 58.5 g
MW PbCl2 = 277 g
2(58.5 g) of NaCl ------------------------ 277 g of PbCl2
25 g of NaCl ------------------------ x
x = (25 x 277) / 117
x = 25 g
