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WARRIOR [948]
1 year ago
12

Perform the following

Chemistry
2 answers:
earnstyle [38]1 year ago
3 0

Answer:

Explanation:

7.3224 because if you add the it is 7.3224 easy math kid

il63 [147K]1 year ago
3 0

Answer:

7.32

Explanation:

This is the actual answer rounded.

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The electron configurations of two unknown elements X and Y are shown . X: 1s^ 2 2s^ 2 2p^ 6 3s^ 1 Y: 1s^ 2 2s^ 1 Which statemen
PIT_PIT [208]

Answer:

See below.

Explanation:

They both have 1 valency electron so will be metallic and in the same Group (Group 1) of the Periodic Table, so will have similar properties.

8 0
3 years ago
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The photograph shows the most abundant substance on Earth's su Which fact about this substance tells you that it is a compound?
rosijanka [135]

Answer:

the answer to this question is b

4 0
3 years ago
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For the oxidation-reduction reaction equation given here 4ga+p4 indicate how many electrons are transferred in the formation of
sergij07 [2.7K]
The reaction given is:

4Ga + P4 ---> 4GaP

The oxidation number of the reactants is zero, because they are pure elements.

The P in compounds may have oxidation states 3- or 5-. Gallium may only have oxidation state 3+.

Then, to be neutral in GaP the oxidation states are 3+ for Ga and 3- for P.

And the transference of electrons can be see in this oxidation - reduction equations:

Ga (0) - 3 e-    ----> Ga (3+)

P (0) + 3e- ---> P (3-)

So, for one formula unit, 3 electrons have been transfered from each Ga atom to P atom to form one GaP unit.

Answer: 3 electrons.
3 0
3 years ago
What is the threshold frequency ν0 of cesium?
Montano1993 [528]
 I think this is what you're after:

 Cs(g) → Cs^+ + e⁻ ΔHIP = 375.7 kJ mol^-1 [1] 


Convert to J and divide by the Avogadro Const to give E in J per photon 


E = 375700/6.022×10^23 = 6.239×10^-19 J 


Plank relationship E = h×ν E in J ν = frequency (Hz s-1) 


Planck constant h = 6.626×10^-34 J s 


6.239×10^-19 = (6.626×10^-34)ν 


ν = 9.42×10^14 s^-1 (Hz) 


IP are usually given in ev Cs 3.894 eV 


<span>E = 3.894×1.60×10^-19 = 6.230×10^-19 J per photon </span>

4 0
3 years ago
Name the region of the atom where protons and neutrons are located.
inn [45]

Answer:

Nucleus

Explanation:

5 0
3 years ago
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