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Tomtit [17]
3 years ago
7

How many grams of hydrogen gas get produced if 10 g of aluminum reacts?

Chemistry
1 answer:
Degger [83]3 years ago
8 0

Answer:

9.8

Explanation:

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PLEASE HELP
Step2247 [10]

Answer:

See explanation

Explanation:

The equation of the reaction is;

C3H8 + 5O2 ----> 3CO2 + 4H2O

Number of moles of C3H8 = 132.33g/44g/mol = 3 moles

1 mole of C3H8 yields 3 moles of CO2

3 moles of C3H8 yields 3 × 3/1 = 9 moles of CO2

Number of moles of oxygen = 384.00 g/32 g/mol = 12 moles

5 moles of oxygen yields 3 moles of CO2

12 moles of oxygen yields 12 × 3/5 = 7.2 moles of CO2

Hence C3H8 is the limiting reactant.

Mass of CO2 produced = 9 moles of CO2 × 44 g/mol = 396 g of CO2

1 moles of C3H8 yields 4 moles of water

3 moles of C3H8 yields 3 × 4/1 = 12 moles of water

Mass of water = 12 moles of water × 18 g/mol = 216 g of water

b) Actual yield = 269.34 g

Theoretical yield = 396 g

% yield = actual yield/theoretical yield × 100/1

% yield = 269.34 g /396 g × 100

% yield = 68%

4 0
3 years ago
PLEASE HELP!
pogonyaev

Answer:

Q = 2.60 • 10^{3} J

Explanation:

Our specific heat capacity equation is:

Q = mC∆T

Q is the energy in joules.

m is the mass of the substance.

∆T is the temperature chance.

Let's plug in what we know.

  • We have 76.0 g of octane
  • The specific heat capacity of octane is 2.22 J/(g•K)
  • The temperature increases from 10.6º to 26.0º (a 15.4º increase)

Q = 76.0(2.22)(15.4)

Multiply.

Q = 2598.288

We want three significant figures.

Q = 2.60 • 10^{3}

or

Q = 2590 J

Hope this helps!

3 0
3 years ago
Read 2 more answers
What is the hardest subject u ever taking, mine is chemistry
artcher [175]

Answer:

Mine is language arts brainliest?

Explanation:

7 0
3 years ago
A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
tino4ka555 [31]

Answer:

2.1 × 10⁻¹ M

2.0 × 10⁻¹ m

Explanation:

Molarity

The molar mass of aniline (solute) is 93.13 g/mol. The moles corresponding to 3.9 g are:

3.9 g × (1 mol/93.13 g) = 0.042 mol

The volume of the solution is 200 mL (0.200 L). The molarity of aniline is:

M = 0.042 mol/0.200 L = 0.21 M = 2.1 × 10⁻¹ M

Molality

The moles of solute are 0.042 mol.

The density of the solvent is 1.05 g/mL. The mass corresponding to 200 mL is:

200 mL × 1.05 g/mL = 210 g = 0.210 kg

The molality of aniline is:

m = 0.042 mol/0.210 kg = 0.20 m = 2.0 × 10⁻¹ m

5 0
3 years ago
Bill's recipe for onion soup calls for 4.0 lb of thinly sliced onions . if an onion has an average mass of 115 g , how many onio
Pavlova-9 [17]

Answer:

A lot

Explanation:

BillBill's recipe for onion soup calls for 4.0 lb of thinly sliced onions . if an onion has an average mass of 115 g , how many onions does Bill need ?

7 0
3 years ago
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