How much heat transfer is necessary to raise the temperature of a 13.6 kg piece of ice from −20.0ºC to 130ºC? specific heat capa
city of water is 4184 J/kg C and specific latent heat of fusion is 334000 J/kg.
8535360 J
4542400 J
458720900 J
13077760 J
1 answer:
Answer:
A: 8535360 J
Explanation:
We are given;
mass; m = 13.6 kg
Initial temperature; T1 = -20° C
Final temperature; T2 = 130° C
Specific heat capacity; c = 4184 J/kg.°C
Specific latent heat of fusion; L = 334000 J/kg.
Since we are dealing with change in temperature, then we will use the heat energy formula for specific heat capacity.
Q = mcΔt
Thus;
Q = 13.6 × 4184 × (130 - (-20))
Q = 13.6 × 4184 × 150
Q = 8535360 J
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