Answer:
Hopefully its true, its seem like true. I think its true. Sorry if i'm wrong
Explanation:
<span>To
solve this we assume that the gas is an ideal gas. Then, we can use the ideal
gas equation which is expressed as PV = nRT. At number of moles the value of PV/T is equal to some constant. At another
set of condition of temperature, the constant is still the same. Calculations
are as follows:</span>
P1V1/T1 = P2V2/T2
P1 = P2V2T1/T2V1
P1 = (114)(1.32)(596)/(715)(.654)
P1 = 191.80 kPa
As there is the increase in Oxidation number from +1 to +2. Hence, the correct Option (A) i.e, 1 to +2,
<h3>
What is Oxidation ?</h3>
Oxidation doesn't necessarily have anything to do with oxygen.
- Oxidation occurs when an atom, molecule, or ion loses one or more electrons in a chemical reaction.
- When oxidation occurs, the oxidation state or oxidation number of the chemical species increases.
- Oxidation doesn't necessarily involve oxygen! Originally, the term was used when oxygen caused electron loss in a reaction.
Hence, Option (A) indicates the oxidation as there is the increase in Oxidation number from +1 to +2.
Learn more about Oxidation here ;
brainly.com/question/13110055
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A. They are the same
<h3>Further explanation</h3>
Given
C3H6 and C4H8
Required
The percent compositions
Solution
%C = 3.12/42 x 100% = 85.71%
%H = 6.1/42 x 1005 = 14.29%
C₄H₈(MW=56 g/mol)
%C = 4.12/56 x 100% = 85.71%
%H = 8.1/56 x 100%=14.29%
So they are the same, because mol ratio of C and H in both compounds is the same, 1: 2