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Volgvan
3 years ago
9

How do the percent compositions for C3H6 and C4H7 compare?

Chemistry
1 answer:
mariarad [96]3 years ago
3 0

A. They are the same

<h3>Further explanation</h3>

Given

C3H6 and C4H8

Required

The percent compositions

Solution

  • C₃H₆(MW = 42 g/mol)

%C = 3.12/42 x 100% = 85.71%

%H = 6.1/42 x 1005 = 14.29%

C₄H₈(MW=56 g/mol)

%C = 4.12/56 x 100% = 85.71%

%H = 8.1/56 x 100%=14.29%

So they are the same, because mol ratio of C and H in both compounds is the same, 1: 2

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Caffeine (C8H10N4O2) is a stimulant found in coffees and teas. When dissolved in water, it can accept a proton from a water mole
Olenka [21]

Answer:

See figure 1

Explanation:

If we want to find the acid and the Brønsted-Lowry base, we must remember the definition for each of these molecules:

-) Acid: hydrogen donor

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In the <u>caffeine structure,</u> we have several atoms of nitrogen. These nitrogen atoms have the ability to <u>accept</u> hydronium ions (H^+). Therefore the caffeine molecule will be the base since it can accept

If caffeine is the base, the water must be the acid. So, the water in this reaction donated a hydronium ion.

<u>Thus, caffeine is the base and water the acid. (See figure 1)</u>

3 0
3 years ago
10 POINTS!!! Which statement best defines a universal law?
Nadya [2.5K]

Answer: Universal law refers to as legal legitimacy,  where those principles and rules are for governing the country. They are most universal in (AATPB) acceptability, applicability, translation, and philosophical basis. They are also considered to be most legitimate.

So basically the answer is A

They are in effect all the time.

Explanation:

Hopefully this helps you

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5 0
3 years ago
What is the concentration of H3O+ ions in saliva if [OH-] = 4.22 x 10-10 M? Provide the pH and the classification of this sample
OLEGan [10]

pH=4.625

The classification of this sample of saliva : acid

<h3>Further explanation</h3>

The water equilibrium constant (Kw) is the product of concentration

the ions:

Kw = [H₃O⁺] [OH⁻]

Kw value at 25° C = 10⁻¹⁴

It is known [OH-] =  4.22 x 10⁻¹⁰ M

then the concentration of H₃O⁺:

\tt 10^{-14}=4.22\times 10^{-10}\times [H_3O^+]\\\\(H_3O^+]=\dfrac{10^{-14}}{4.22\times 10^{-10}}=2.37\times 10^{-5}

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6 0
3 years ago
Acetylene is hyrodgenated to form ethane. The feed to the reactor contains 1.60 mol H2/mol C2H2. The reaction proceeds to comple
Black_prince [1.1K]

Answer:

Explanation:

C₂H₂     +   2H₂   =     C₂H₆

1 mole     2 mole        1 mole

Feed of reactant is 1.6 mole H₂ / mole C₂H₂

or 1.6 mole of H₂ for 1 mole of C₂H₂

required ratio as per chemical reaction written above

2 mole of  H₂ for 1 mole of C₂H₂

So H₂ is in short supply . Hence it is limiting reagent .

1.6 mole of H₂ will react with half of 1.6 mole or .8 mole of C₂H₂ to form .8 mole of C₂H₆

a )Calculate the stoichiometric reactant ratio =  mole H₂ reacted/mole C₂H₂ reacted

= 1.6 / .8 = 2 .

b )

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4 0
3 years ago
Calculate the molarity of a solution with 114.95 grams of sodium dissolved in 2 L of water. ​
koban [17]

Answer:

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Explanation:

Molarity is a concentration unit that describes how much of a solution is dissolved in solution.

Molarity of a solution can found by using the formula,

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Given, mass of Sodium = 114.95 grams.

Volume of water = 2 L.

Here, Sodium is solute as it is dissolved in water, which is the solvent.

Moles of Sodium(solute) can be found by using the formula,

Number of Moles = mass/Molecular weight.

mass of Sodium = 114.95 grams.

Molecular weight = 22.989 grams

Number of Moles of Sodium(solute) =114.95/22.989 = 5.

Substituting the values in the formula, we get,

M = 5/2 = 2.5 M

3 0
3 years ago
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