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Volgvan
3 years ago
9

How do the percent compositions for C3H6 and C4H7 compare?

Chemistry
1 answer:
mariarad [96]3 years ago
3 0

A. They are the same

<h3>Further explanation</h3>

Given

C3H6 and C4H8

Required

The percent compositions

Solution

  • C₃H₆(MW = 42 g/mol)

%C = 3.12/42 x 100% = 85.71%

%H = 6.1/42 x 1005 = 14.29%

C₄H₈(MW=56 g/mol)

%C = 4.12/56 x 100% = 85.71%

%H = 8.1/56 x 100%=14.29%

So they are the same, because mol ratio of C and H in both compounds is the same, 1: 2

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What is the ratio of [a–]/[ha] at ph 3.75? the pka of formic acid (methanoic acid, h–cooh) is 3.75?
nataly862011 [7]
To determine the ratio of [a–]/[ha] of a solution of formic acid, we use the Henderson–Hasselbalch equation which relates the pH, pKa and the concentration of the ions in the solution. It is expressed as:

pH = pkA + log [a–]/[ha]

Substituting the values given,

3.75 = 3.75 + log [a–]/[ha]
0 = log [a–]/[ha]
[a–]/[ha] = 1

Therefore, the concentration of the CHOO- ion and the formic acid are equal.
5 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 1000 j of heat, starting from 20°c?
allochka39001 [22]

The amount of maximum mass of ethyl alcohol that could we boil with 1000 J of heat, starting from 20°C is 7.08 grams.

<h3>How do we calculate the mass?</h3>

Mass of the ethyl alcohol will be calculated by using the below equation as:

Q = mcΔT, where

  • Q = absorbed heat = 1000 J
  • m = mass of ethyl alcohol = ?
  • c = specific heat of ethyl alcohol = 2.42 J/g.°C
  • ΔT = change in temperature = (78.37°C - 20°C) = 58.37°C

On putting all these values, we get

m = 1000 / (2.42)(58.37) = 7.079 = 7.08g

Hence required mass of ethyl alcohol is 7.08grams.

To know more about absorbed heat, visit the below link:
brainly.com/question/16559442

#SPJ4

6 0
3 years ago
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Answer:

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Explanation:

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In your own words, define measuring.
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4 years ago
Can anyone help me on this please.
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8 0
3 years ago
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