Answer:
= 14.88 N
Explanation:
Let's begin by listing out the given variables:
M = 2.7 kg, L = 3 m, m = 1.35 kg, d = 0.6 m,
g = 9.8 m/s²
At equilibrium, the sum of all external torque acting on an object equals zero
τ(net) = 0
Taking moment about
we have:
(M + m) g * 0.5L -
(L - d) = 0
⇒
= [(M + m) g * 0.5L] ÷ (L - d)
= [(2.7 + 1.35) * 9.8 * 0.5(3)] ÷ (3 - 0.6)
= 59.535 ÷ 2.4
= 24.80625 N ≈ 24.81 N
Weight of bar(W) = M * g = 2.7 * 9.8 = 26.46 N
Weight of monkey(w) = m * g = 1.35 * 9.8 = 13.23 N
Using sum of equilibrium in the vertical direction, we have:
+
= W + w ------- Eqn 1
Substituting T2, W & w into the Eqn 1
+ 24.81 = 26.46 + 13.23
= <u>14.88</u> N
Answer:
Power of the speakers = 1.57 
Explanation:
There are speakers setup in a park and we have to find the power it would require to have intensity of sound to be
at a distance of 5 meter.
In one dimension the intensity is constant as the wave travels. In two or three dimensions, however, the intensity decreases as you get further from the source.
Intensity is inversely proportional to the square of the distance from the point of sound production.
Here area = 2
area = 157 


Power = ![10^{-8} \times 157Power = 1.57 [tex]\times 10^{-6} W](https://tex.z-dn.net/?f=10%5E%7B-8%7D%20%5Ctimes%20157%3C%2Fp%3E%3Cp%3E%3Cstrong%3EPower%20%3D%201.57%20%5Btex%5D%5Ctimes%2010%5E%7B-6%7D%20W)
Answer: it’s in the picture
Explanation: look at the picture