Answer:
The instantaneous velocity of the object is 250 m/s
Explanation:
Given;
time of the object motion, t = 25 s
acceleration due to gravity, g = 10 m/s²
The instantaneous velocity of the object is given as;
v = u + gt
where;
u is the initial velocity of the object = 0 (since it was released from rest)
Substitute the givens;
v = 0 + (10 x 25)
v = 250 m/s
Therefore, the instantaneous velocity of the object is 250 m/s
It will lead to rain. I know this because as the clouds move over water sources like oceans, lakes, and rivers, the water evaporates and rises. The water then liquefies into little water droplets. As the cloud moves over more water the droplets get scrunched up and get bigger over time and soon they get heavy and gravity pulls the droplets down to earth as rain. The End.
Answer:
-7.14
Explanation:
According to equation of motion
v = u + at
where
v is the final velocity at any time t
u is the initial velocity
a is the acceleration
and t is the time
___________________________________________
Given
An object is thrown upward it means
its initial velocity is in upward direction
but acceleration due to gravity is in downward direction which will cause to decrease the velocity of object.
Intial velocity u = 31.1 m/s
final velocity v at 4 second we have to find.
t = 4 second
a = g = 9.81 m/s2 (it is acting in opposite direction of motion hence its sign will be negative ).
Thus
a = - 9.81 m/s2
using the above values in v = u + at
v = 32.1 - 9.81*4
v = 32.1 - 39.24
v = -7.14
Thus, correct option is -7.14.
Explanation:
33. The 1.5kg owl is now soaring at 20m/s. What is the owl’s KE?
a. Step 1: Formula <u>½mv²</u>
b. Step 2: Data m = <u>1</u><u>.</u><u>5</u><u> </u><u>kg</u>, v = <u>2</u><u>0</u><u> </u><u>m</u><u>/</u><u>s</u>
c. Step 3: Solve
KE = (1/2)(<u>1</u><u>.</u><u>5</u>)(<u>2</u><u>0</u>)² = <u>3</u><u>0</u><u>0</u><u> </u><u>J</u>