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lapo4ka [179]
3 years ago
8

Which atom in a water molecule has the greatest electronegativity??

Physics
1 answer:
galina1969 [7]3 years ago
7 0
The oxygen atom in a water molecule has the greatest and or highest electronegativity, it has the greatest ability of all of the elements in a water molecule, 2, to pull electrons closer towards its own atom.
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A car's horn produces a constant frequency of 350 Hz as it passes by Suzy. What is the best estimate of the
Arada [10]

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330 Hz

Explanation:

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An electrician timed a box traveling over a conveyor and measured 25 sec to travel 30 feet. If the gearbox ratio is 20:1 and the
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4 years ago
A watering can is most likely measured in which metric unit
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A watering can is used to hold a water that we will use to water the plants. The water has both mass and volume. Two watering cans are most often different by the volume they contain. 

Many various units for volume are used but most often used unit is liter. In a metric system basic units are those such as meter, kilogram and liter while in imperial system units used are those such as foote, inch, pound and gallon.

Unit for volume in metric system is cubic meter. It is equal to a volume of a cube whose all sides measure 1m. This is equal to 1000L. For watering cans that contain several liters units used is decimeter cubed. 1dm^3 = 1L
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3 years ago
Explain the meaning and use of the following acronyms: HELIOS, Exo-FMS, HAZMAT, NIRSpec.​
adelina 88 [10]

Answer:

HELIOS- The god of the sun in

HAZMAT-Hazardous materials

NIRSpec- Near Infrared Spectrograph

Explanation:

4 0
2 years ago
Two pianos each sound the same note simultaneously, but they are both out of tune. On a day when the speed of sound is 349 m/s,
SSSSS [86.1K]

Answer:

Time period between the successive beats will be 0.1703 sec

Explanation:

We have given speed of the sound v = 349 m/sec

Wavelength of piano A\lambda _A=0.766m

Wavelength of piano  B\lambda _B=0.776m

So frequency of piano A f_1=\frac{v}{\lambda _1}=\frac{349}{0.766}=455.61Hz

Frequency of piano B f_2=\frac{v}{\lambda _1}=\frac{349}{0.776}=449.74Hz

So beat frequency f = 455.61 - 449.74 = 5.87 Hz

So time period T=\frac{1}{f}=\frac{1}{5.87}=0.1703sec

So time period between the successive beats will be 0.1703 sec

4 0
4 years ago
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