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Contact [7]
3 years ago
10

Anyone have the electromagnetic induction lab? help fast pls

Physics
1 answer:
Ivenika [448]3 years ago
5 0

Answer:

In 1831, Michael Faraday carried out numerous experiments to prove that electricity could be generated from magnetism. He not only demonstrated electromagnetic induction, but also developed a good conception of the processes involved.

In 1831, Michael Faraday carried out numerous experiments in his attempt to prove that electricity could be generated from magnetism. Within the course of a few weeks, the great experimentalist not only had clearly demonstrated this phenomenon, now known as electromagnetic induction, but also had developed a good conception of the processes involved. One of the experiments performed by Faraday in that important year featured a permanent magnet and a galvanometer connected to a coil of wire wound around a paper cylinder, similar to those illustrated in this tutorial.

To simulate Faraday’s experiment, click and drag the bar magnet back and forth inside of the coil. Observe that the voltmeter linked to the coil only indicates the presence of a current when the magnet is actually in motion, and that its needle deflects in one direction when the magnet is moved into the coil and in the opposite direction when it is dragged out of the coil. Also note the magnetic field lines, depicted in blue, emanating from the magnet, and how the direction of the current (indicated in black arrows) changes depending on which way the magnet is moving. As you can observe, when the north end of the magnet enters the coil, a current is induced that travels around the coil in a counterclockwise direction; when the magnet is then pulled out of the coil, the direction reverses to clockwise.

Also notice that the current produced is stronger when the magnet is moved quickly rather than gradually. Adjust the number of turns slider and move the magnet in and out of the coil again to determine the relationship between the turns of wire in the coil and the current induced in that coil. As indicated by the voltmeter, greater voltage can be induced in coils made from a larger number of turns of wire.

Use the blue flip magnet button to see how things change when the south end of the magnet, exhibiting different field lines, interacts with the coils of wire.

In this demonstration of electromagnetic induction, the mechanical energy of the moving magnet is converted into electricity, because a moving magnetic field, entering a conductor, induces current to flow in the conductor. What also happens (though not illustrated in this tutorial) is that the current that has been induced in the wire, in turn, generates another magnetic field around the wire. This field opposes the field of the moving magnet, as explained by Lenz’s Law.

Explanation:

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una onda longitudinal tiene una frecuencia de 200 hz y una longitud de onda de 4.2m ¿cual es la rapidez de la onda?​
swat32

Answer:

v = 8.4 m/s

Explanation:

The question ays, "A longitudinal wave has a frequency of 200 Hz and a wavelength of 4.2m. What is the speed of the wave?".

Frequency of a wave, f = 200 Hz

Wavelength = 4.2 cm = 0.042 m

We need to find the speed of the wave. The formula for the speed of a wave is given by :

v=f\lambda\\\\v=200\times 0.042\\\\=8.4\ m/s

So, the speed of the wave is equal to 8.4 m/s.

4 0
3 years ago
Based on this passage, what is campylobacter?
alexdok [17]
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4 0
3 years ago
Read 2 more answers
A 2:2 kg toy train is con ned to roll along a straight, frictionless track parallel to the x-axis. The train starts at the origi
Liula [17]

Answer:

a) 10.51 J

b) 3.48 m/s

Explanation:

Given data :

mass of train ( M ) = 2.2 kg

Given initial velocity ( u ) = 1.6 m/s

<u>a) calculating work done by the force over the journey of the train</u>

F = mx + b  ------ ( 1 )

m = slope  = ( Δ f / Δ x ) = 2.8 / -7.5 = - 0.373 N/m

x = distance travelled on the x axis by the train = 7.5 m

F = force experienced by the train = 2.8 N

x = 0

∴ b = 2.8

hence equation 1 can be written as

F = ( -0.373) x + 2.8   ----- ( 2 )

hence to determine the work done by the force

W   = \int\limits^7_0 { ( -0.373) x + 2.8  )} \, dx     Note:  the limits are actually 7.5 and 0

∴ W ( work done ) = -10.49 + 21 = 10.51 J

<u>b) calculate the speed of the train at the end of its journey</u>

we will apply the work energy theorem

W = 1/2 m*v^2  -  1/2 m*u^2

∴ V^2 = 2 / M ( W + 1/2 M*u^2 )  ( input values into equation )

 V^2 = 12.11

hence V = 3.48 m/s

6 0
3 years ago
Suppose a 4.0-kg projectile is launched vertically with a speed of 8.0 m/s. What is the maximum height the projectile reaches?
eduard

Answer:

h = 3.3 m (Look at the explanation below, please)

Explanation:

This question has to do with kinetic and potential energy. At the beginning (time of launch), there is no potential energy- we assume it starts from the ground. There, is, however, kinetic energy

Kinetic energy = \frac{1}{2}mv^{2}

Plug in the numbers = \frac{1}{2}(4.0)(8^{2})

Solve = 2(64) = 128 J

Now, since we know that the mechanical energy of a system always remains constant in the absence of outside forces (there is no outside force here), we can deduce that the kinetic energy at the bottom is equal to the potential energy at the top. Look at the diagram I have attached.

Potential energy = mgh = (4.0)(9.8)(h) = 39.2(h)

Kinetic energy = Potential Energy

128 J = 39.2h

h = 3.26 m

h= 3.3 m (because of significant figures)

7 0
3 years ago
A pail in a water well is hoisted by means of a frictionless winch, which consists of a spool and a hand crank. When Jill turns
Sveta_85 [38]

Answer:

182.28 W

Explanation:

Here ,

m = 7.30 Kg

distance , d= 28.0 m

time , t = 11.0 s

average power supplied = change in potential energy/time

average power supplied = m×g×d/time

average power supplied = 7.30×9.81×28/11

average power supplied = 182.28 W

the average power supplied is  182.28 W

6 0
2 years ago
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