Half life is the time taken by a radioactive isotope to decay by half its original mass. In this case, the halflife of the radioactive isotope is 5000 years.
Initially the mass is 100 %; thus the mass that will be left will be given by;
New mass = Original mass × (1/2)^n where n is the number of half lives;
n = 10000/5000 = 2
New mass = 100% ×(1/2)^2
= 100 % × 1/4
= 25%
Therefore; the mass left after 10000 years is 25% or 1/4 of the original mass.
I think it is called condensated matter
Answer:
Ecel =0,04 V
Explanation:
Apply the Nerst equation,
Ecel= Ecelº - (RT/nF)*lnQ
where R=8,314 J/molK, T=25ºC=298K and F =96 485 Coulombs/mol e- and n=number of moles of electrons transferred in the balanced equation. Q is cocient of products and reactives power to respective coefficients, if is a gas apply partial pressure
Write the semiequation redox and verify the numbers of electron for balance. In this case you don't need to change nothing
2Cl−(aq)→Cl2(g) + 2e-
<u>2CO3+(aq) + 2e-→2CO2+(aq)</u>
2Cl−(aq) + <u>2CO3+(aq) </u>→<u>2CO2+(aq) + </u>Cl2(g)
Hence
Ecel= 0.483 V - 0.013Ln ([CO2+]^2*PCl2] / [CO3+]^2*[Cl-]^2)
Ecel= 0.483 V - 0.013Ln ([0.205]^2 * 7.3] / [0.19]^2*[0.144]^2)
Ecel =0,04 V
Answer:
2p
Explanation:
Boron is a member of group 13. The highest energy sub-level is usually found on the outermost shell of the atom of the element involved.
For a group 13 element, its outermost shell configuration is ns2 np1. The electronic configuration for boron is; 1s2 2s2 2p1.
Hence the highest energy sub-level in boron is 2p.