Answer:
Workdone = 1.96 Nm
Explanation:
Given the following data;
Mass = 100g to kg 100/1000 = 0.1Kg
Distance = 2m
To find the workdone;
First of all, we would determine the force acting on the apple
Force = mass * acceleration due to gravity
But, acceleration due to gravity is equal to 9.8m/s²
Force = 0.1 * 9.8
Force = 0.98N
Now, we can find the workdone using the formula;
Workdone = force* distance
Substituting into the equation, we have
Workdone = 0.98 * 2
Workdone = 1.96 Nm
Answer: a = 0.647 m/s^2
Explanation:
Acceleration = change in speed / time → a = 22 / 34 → a = .647 m/s^2
What? Can you take a picture of the question please?
Answer:
(a i - 2a j) / 2
Explanation:
a1 = a i
a2 = a j
a3 = - (i + j) (2a) = - 2a i - 2a j
a4 = (i - j) (3a) = 3a i - 3a j
Let the mass of each particle is m.
Use the formula of acceleration of centre of mass
a cm = (m1 a1 + m2 a2 + m3 a3 + m4 a4) / (m1 + m2 + m3 + m4)
a cm = (a i + aj - 2a i - 2a j + 3a i - 3a j) / 4
a cm = ( 2a i - 4a j) / 4
a cm = (a i - 2a j) / 2
Answer:
The time period of the empty car will be "1.00 s".
Explanation:
The given values in the question will be:
Mass,
m = 250 kg
Loaded car's time period will be:
T = 1.08 s
Shock absorbers compression,
x = 4 cm
or,
= 0.04 m
Now,
Weight of passengers will be:
⇒ ![F=mg](https://tex.z-dn.net/?f=F%3Dmg)
![=250\times 9.8](https://tex.z-dn.net/?f=%3D250%5Ctimes%209.8)
![=2450 \ N](https://tex.z-dn.net/?f=%3D2450%20%5C%20N)
The spring constant of shock absorbers will be:
⇒ ![k=\frac{F}{x}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7BF%7D%7Bx%7D)
![=\frac{2450}{0.04}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2450%7D%7B0.04%7D)
![=61.250 \ N/m](https://tex.z-dn.net/?f=%3D61.250%20%5C%20N%2Fm)
As we know,
Time period, ![T = 2 \pi\sqrt{\frac{M}{k} }](https://tex.z-dn.net/?f=T%20%3D%202%20%5Cpi%5Csqrt%7B%5Cfrac%7BM%7D%7Bk%7D%20%7D)
On substituting the values, we get
![1.08=2\pi \sqrt{\frac{M}{61250} }](https://tex.z-dn.net/?f=1.08%3D2%5Cpi%20%5Csqrt%7B%5Cfrac%7BM%7D%7B61250%7D%20%7D)
![\frac{M}{61250}=0.02955](https://tex.z-dn.net/?f=%5Cfrac%7BM%7D%7B61250%7D%3D0.02955)
![M=0.02955\times 61250](https://tex.z-dn.net/?f=M%3D0.02955%5Ctimes%2061250)
(Total mass of car as well as its passengers)
Now,
The mass of the empty car will be:
⇒ ![m'=M-m](https://tex.z-dn.net/?f=m%27%3DM-m)
![=1809.6-250](https://tex.z-dn.net/?f=%3D1809.6-250)
![=1559.6 \ kg](https://tex.z-dn.net/?f=%3D1559.6%20%5C%20kg)
hence,
The time period of empty car will be:
⇒ ![T'=2\pi\sqrt{\frac{m'}{k} }](https://tex.z-dn.net/?f=T%27%3D2%5Cpi%5Csqrt%7B%5Cfrac%7Bm%27%7D%7Bk%7D%20%7D)
![=2\pi\sqrt{\frac{1559.6}{61250} }](https://tex.z-dn.net/?f=%3D2%5Cpi%5Csqrt%7B%5Cfrac%7B1559.6%7D%7B61250%7D%20%7D)
![=2\pi \sqrt{0.0254}](https://tex.z-dn.net/?f=%3D2%5Cpi%20%5Csqrt%7B0.0254%7D)
![=1.003 \ s](https://tex.z-dn.net/?f=%3D1.003%20%5C%20s)
or,
![=1.00 \ s](https://tex.z-dn.net/?f=%3D1.00%20%5C%20s)