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Citrus2011 [14]
3 years ago
13

Whiteout friction you could not, write, drive or fly and airplane. Why not?

Physics
1 answer:
aleksklad [387]3 years ago
7 0

friction is the resistance that one surface or object encounters when moving over another. Due to gravity pulling everything down things need to friction in order to move

i hope this helps :/


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Find the west component of 45 m 19º S of W
BaLLatris [955]

Answer:

The west component of the given vector is - 42.548 meters.

Explanation:

We need to translate the sentence into a vectoral expression in rectangular form, which is defined as:

(x, y) = (r_{x}, r_{y})

Where:

r_{x} - Horizontal component of vector distance, measured in meters.

r_{y} - Vertical component of vector distance, measured in meters.

Let suppose that east and north have positive signs, then we get the following expression:

(x, y) = (-45\cdot \cos 19^{\circ}, -45\cdot \sin 19^{\circ})\,[m]

(x, y) = (-42.548,-14.651)\,[m]

The west component corresponds to the first component of the ordered pair. That is to say:

x = -42.548\,m

The west component of the given vector is - 42.548 meters.

8 0
4 years ago
True or false compounds only have one type of element
klasskru [66]

False, Compounds can contain more than 2 elements.

8 0
3 years ago
What are the forces that make an object move
Vaselesa [24]
There are many forces that make an object move.

· An Unbalanced force acting on an object

· Energy applied to an object.


3 0
3 years ago
The speaker at the concert has the sound intensity level of 100 dB if we listen from the distance 5 m.How far from the speaker d
Mademuasel [1]

Answer:

28.11m far from the speaker the intensity drops to 85 dB.

Explanation:

In the equation for the Decibel scale

  (1). \: \:\beta =10 log(\dfrac{I}{I_0})

The ratio of the intensities can be written as

$ \frac{I}{I_0} = \dfrac{\frac{P}{A} }{\frac{P}{A_0} } $

\dfrac{I}{I_0} = \dfrac{A_0}{A}.

And since

A = 4\pi r^2

and

A_0 = 4 \pi r_0^2,

\dfrac{A_0}{A} = \dfrac{4 \pi r_0^2}{4 \pi r^2}  = \dfrac{r_0^2}{r^2}

meaning

\dfrac{I}{I_0} = \dfrac{r_0^2}{r^2}.

Putting this into equation (1), we get:

\boxed{ (2).\: \: \beta = 10log(\dfrac{r_0^2}{r^2})}

Now, if the intensity is 100 dB when the distance is 5 meters, we have:

100dB=10 log(\dfrac{r_02}{(5m)^2})

10= log(\dfrac{r_0^2}{25})

by taking both sides to the exponent:  

10^{10}= \dfrac{r_0^2}{25}

r^2 = 25 *10^{10}\\r = 5 *10^5

Now equation (2) becomes

\beta = 10log(\dfrac{25*10^{10}}{r^2})

when the intensity level is 85 dB we have

85 = 10log(\dfrac{25*10^{10}}{r^2})

8.5 = log(\dfrac{25*10^{10}}{r^2})

take both sides to exponents and we get:

10^{8.5} =10^{ log(\dfrac{25*10^{10}}{r^2})}

10^{8.5} =\dfrac{25*10^{10}}{r^2}

r^2 = \dfrac{25*10^{10}}{10^{8.5}}

\boxed{r = 28.11m}

Thus, 28.11m far from the speaker the intensity drops to 85 dB.

7 0
3 years ago
NEED HELP ASAP
raketka [301]

Answer:

50km/h

Explanation:

my teatcher said that

7 0
4 years ago
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