3 years ago

At which moon position would a person on Earth see the entire half of the moon(full-moon)?

Physics

2 answers:

iragen [17]3 years ago

8 0

Wouldn't that be the full moon position...its position 5...idk know what its asking for exactly..what are your choices?

jeka943 years ago

3 0

Sun-earth-moon in a straight line. Earth in the 'middle'.

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A baseball has a mass of 0.15kg .What is the net force on the ball if it's acceleration is 40.0m/sw

kvasek [131]

By Newton's second law, we have

$F=ma$

So, in order to give a 0.15kg body an acceleration of 40m/s^2, you need a force of

$F=0.15\cdot 40 = 6N$

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4 years ago

An air-conditioner with refrigerant-134a as the working fluid is used to keep a room at 238C by rejecting the waste heat to the

tatiyna

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3 years ago

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) A) 0.6976

soldier1979 [14.2K]

Answer:

The speed of the stone is 0.6138 c.

(B) is correct option.

Explanation:

Given that,

Mass of stone m= 0.6

Relativistic mass = 0.76

We need to calculate the speed

Using formula of rest mass

$m_{r}=\dfrac{m_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}$

$v^2=(\dfrac{m_{0}^2}{m_{r}^2}-1)c^2$

Put the value into the formula

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3 years ago

In your discussion entry, create and describe at least four ways to include someone of a diverse culture or ability level in a s

artcher [175]

The answer is: playing area

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3 years ago

On a balanced seesaw, a boy three times as heavy as his partner sits

slega [8]

Answer:

1/3 the distance from the fulcrum

Explanation:

On a balanced seesaw, the torques around the fulcrum calculated on one side and on another side must be equal. This means that:

$W_1 d_1 = W_2 d_2$

where

W1 is the weight of the boy

d1 is its distance from the fulcrum

W2 is the weight of his partner

d2 is the distance of the partner from the fulcrum

In this problem, we know that the boy is three times as heavy as his partner, so

$W_1 = 3 W_2$

If we substitute this into the equation, we find:

$(3 W_2) d_1 = W_2 d_2$

and by simplifying:

$3 d_1 = d_2\\d_1 = \frac{1}{3}d_2$

which means that the boy sits at 1/3 the distance from the fulcrum.

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4 years ago