L=2W+3, A=LW, using L from the first in the second gives you:
A=(2W+3)W
A=2W^2+3W, and we are told A=90 so
2W^2+3W=90
2W^2+3W-90=0
2W^2-12W+15W-90=0
2W(W-6)+15(W-6)=0
(2W+15)(W-6)=0, since W>0 for all real possibilities,
W=6ft, and since L=2W+3
L=15ft
So the pool will be 6 ft wide by 15 ft long.
1. The problem says that the television has a rectangular shape. So, the formula for caculate the area of a rectangle is:
A=LxW
"A" is the area of the rectangle (A=3456 inches²).
"L" is the the length of the rectangle.
"W" is the width of the rectangle.
2. The <span>width of the screen is 24 inches longer than the length. This can be expressed as below:
W=24+L
3. Then, you must substitute </span>W=24+L into the formula A=LxW:
<span>
</span>A=LxW
<span> 3456=L(24+L)
3456=24L+L</span>²
<span>
4. The quadratic equation is:
L</span>²+24L-3456=0
5. When you solve the quadratic equation, you obtain:
L=48 inches
6. Finally, you must substitute the value of the length, into W=24+L:
W=24+L
W=24+48
W=72 inches
7. Therefore, the dimensions of the screen are:
L=48 inches
W=72 inches<span> </span>
Answer:
yes
Step-by-step explanation:
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Answer:
b
Step-by-step explanation:
