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3 years ago

I need help solving this i tried and tired but still don’t understand. Factor out the greatest common factor. 6x^5+4x^3+8x=

Mathematics

2 answers:

Yakvenalex [24]3 years ago

4 0

Answer:

Add and subtract the second term to the expression and factor by grouping.

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Step-by-step explanation:

pogonyaev3 years ago

4 0

Answer:

3x⁴+2x²+8

Step-by-step explanation:

$6 {x}^{5} + 4 {x}^{3} + 8x$

$= 2x(3 {x}^{4} + 2 {x}^{2} + 8)$

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Who ever answers this first will get a brainlest

Mrac [35]

Answer:

Well assuming you don’t need to simplify

44/100

0.44

44%

Step-by-step explanation:

Okay so fraction is easy, theres a 100 cubes in total, 44 are shaded in, 44/100 are shaded in which is the area in this scenario.

Decimal is basically moving the place area by a specific amount, in this case theres no whole number since the whole number is 1 or 100/100 and its 44/100 right now so it can’t be a whole number. Decimals go by tenths, hundreths, thousandths, etc. so in this case 44/100 is n the hundreth place since its over a hundred so its 0.44. Or you can move it twice to the right by the times of 0 that appears.

Percent basically means out of 100. So in this case its 44 out of a hundred or 44%

7 0

3 years ago

Read 2 more answers

Decide if the expression is positive or negative. Explain in words how you know, please.

AysviL [449]

Step-by-step explanation:

The first expression is :

$-11\times \dfrac{2}{3}$

Numerator = -11×2 = -22

Denominator = 3

So, answer will be :

$-11\times \dfrac{2}{3}=\dfrac{-22}{3}$ (negative)

The second expression is:

$-11\times \dfrac{-2}{3}$

Numerator = -11×-2 = 22

Denominator = 3

So, the answer will be :

$-11\times \dfrac{-2}{3}=\dfrac{22}{3}$ (positive)

Hence, this is the required solution.

7 0

2 years ago

Prove this trigonometric equation;<br><br> - tan^2x + sec^2x = 1,

alekssr [168]

Hey there :)

- tan²x + sec²x = 1 or 1 + tan²x = sec²x

sin²x + cos²x = 1
Divide the whole by cos²x

$\frac{sin^2x}{cos^2x} + \frac{cos^2x}{cos^2x} = \frac{1}{cos^2x}$

$\frac{sinx}{cosx} = tanx$ so $\frac{sin^2x}{cos^2x} = tan^2x$
and
$\frac{1}{cosx} = secx$ so $\frac{1}{cos^2x} = sec^2x$

Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}

1 = - tan²x = sec²x or sec²x - tanx = 1

3 0

3 years ago

Solve for r 5(r-10)= -51

Sloan [31]

Answer:

r= -1/5

Step-by-step explanation:

Step 1: Remove the parentheses (5r-10= -51)

Step 2: Move the constant to the right-hand side and change the sign (5r= -51 + 50)

Step 3: Calculate the sum of -51 +50 (5r = -1)

Last Step: Divide both sides by the equation by 5 (r = -1/5)

4 0

3 years ago

What is the following sum? ^3√125x^10y^13+^3√27x^10y^13

Nat2105 [25]

8x^3y^4(3 sqrt xy) LETTER A :)

7 0

3 years ago

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