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3 years ago

10

if during a given month your average daily credit card balance is 800 and your yearly interest rate is 17%, how much interest do

you owe on your credit card for that month

2 answers:

lesya692 [45]3 years ago

8 0

Hi there

Interest you owe=
Average daily balance×monthly rate
Interest you owe
800×(0.17÷12)=11.33

Hope it helps

Vlad [161]3 years ago

6 0

If during a given month your average daily credit card balance is $800 and your yearly interest rate is 17%, then the interest you owe on your credit card for that month would be: $11.33

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Galina-37 [17]

Step-by-step explanation:

$= { ({16}^{ \frac{3}{2} } )}^{ \frac{1}{2} }$

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$= {2}^{4 \times \frac{3}{2} \times \frac{1}{2} }$

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The answer is B.

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How do you solve 8 -x = 20

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$8-x=20\\-x=12\\x=-12$

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3 years ago

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Divide 33 photos into two groups so the ratio is 4 to 7

Advocard [28]

4 to 7
or
4+7= 12
4x+7x=33
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3 years ago

40% of what number is 24

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40% of what number is 24

24 : 40 * 100 =

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3 years ago

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

<em>Hence, the smallest sum is 2</em>

3 0

3 years ago