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11Alexandr11 [23.1K]
3 years ago
11

Explain how the nebular model accounts for the differences between the terrestrial and gas giant planets.

Physics
1 answer:
anygoal [31]3 years ago
4 0
Is there any Examples/Answers or is it simply just explain it in a text box?

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A plane starting at rest at one end of a runway undergoes a uniform acceleration of 4.8 m/s
yKpoI14uk [10]
  • initial velocity=0m/s=u
  • Acceleration=a=4.8m/s^2
  • Time=t=15s

Final velocity be v

\\ \sf\longmapsto v=u+at

\\ \sf\longmapsto v=0+4.8(15)

\\ \sf\longmapsto v=72m/s

8 0
2 years ago
a 1020-hertz sound wave travels at 340 m/s in air with a wavelength of a) 30 m. b) 3 m. c) 0.333 m. d) 1 m. e) none of the above
eimsori [14]

The wavelength of the sound wave is equal to 0.333 m. Therefore, option (c) is correct.

<h3>What are frequency and wavelength?</h3>

The frequency of the wave can be defined as the number of oscillations that occur in one second and can be expressed in hertz. The wavelength can be defined as the distance between the two adjacent points of a wave such as two crests or troughs.

The relationship between frequency (ν), speed of sound waves (V), and  wavelength (λ):

V = νλ

Given, the frequency of the sound wave, ν = 10 Hz

The speed of the sound wave,V = 340 m/s

The wavelength of the sound waves can determine as follows

λ = V/ν = 340/1020 = 0.333 m.

Therefore, the wavelength of the sound wave is 0.333 m

Learn more about wavelength and frequency, here:

brainly.com/question/18651058

#SPJ1

5 0
1 year ago
A car has a uniform velocity of 108km/h. How far does it travel in 30 seconds?​
natita [175]
  • Velocity=108km/h

Convert to m/s

\\ \tt\longmapsto 108\times \dfrac{5}{18}

\\ \tt\longmapsto 30m/s

  • Time=30s.

\\ \tt\longmapsto Distance=Velocity\times Time

\\ \tt\longmapsto Distance=30(30)

\\ \tt\longmapsto Distance=900m

6 0
3 years ago
A car is initially moving at 20 m/s east and a little while later it is moving at 10 m/s north. Which of the following best desc
Nina [5.8K]

Answer:d

Explanation:

Given

First car is moving  towards east with velocity 20 m/s

\vec{v_1}=20\hat{i}

then it turns towards north then velocity is  

\vec{v_2}=10\hat{j}

suppose car takes t sec to change its path so average acceleration is given by

a=\frac{v_2-v_1}{t}

a=\frac{1}{t}(10\hat{j}-20\hat{i})

So average  acceleration is towards North of west.

5 0
3 years ago
Ever love a subject but then you realised the subject dosen't love you back..
viktelen [127]
Yes sirrr but at least you know now
7 0
2 years ago
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