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11Alexandr11 [23.1K]
3 years ago
11

Explain how the nebular model accounts for the differences between the terrestrial and gas giant planets.

Physics
1 answer:
anygoal [31]3 years ago
4 0
Is there any Examples/Answers or is it simply just explain it in a text box?

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Wнιcн deмonѕтraтeѕ condυcтιon
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What is avarage speed? (AS)<br>speed?​
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A tank whose bottom is a mirror is filled with water to a depth of 20.0 cm. A small fish floats motionless 7.0 cm under the surf
liberstina [14]

Answer:

The apparent depth of (a) the fish is 5.3 cm and (b) the image of the fish is 24.8 cm.

Explanation:

According to the following equation:

\frac{n_{w} }{s} +\frac{n_{a} }{s'} = \frac{n_{a}- n_{w}}{R_{c} } \\

where <em>nw</em> and <em>na</em> is the refractive indices of water (1.33) and air (1.00) respectively; <em>s</em> is the depth of the fish below the surface of the water; s' is the apparent depth of the fish from normal incidence and Rc is the radius of curvature of the mirror at the bottom of the tank.

Note that the bottom of the tank is assumed to be a flat mirror, therefore the radius of curvature is very large (R⇒∞).

Therefore, the above equation can be expressed as:

\frac{n_{w}}{s} +\frac{n_{a}}{s'}=0

Now we can solve for the apparent depth of the fish.

(a) s'=-(\frac{n_{a}}{n_{w}})x s (Make s' subject of the formula from the above equation)

s'=(\frac{1.00}{1.33} )x7cm

∴ s'=5.3 cm.

(b) The motionless fish floats 13 cm above the mirror, therefore the image of the fish will be situated at 13 + 20 =33 cm away from the real fish.

Therefore, s = 33 cm

s'=-(\frac{n_{a}}{n_{w}})x s

s'=(\frac{1.00}{1.33} )x 33 cm

s'=24.8 cm.

NB: Here, it is assumed that the water is pure, as impurities may alter the refractive index of water.

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Answer:

idk sorry

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