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balandron [24]
2 years ago
12

An air track car with a mass of 6 kg and velocity of 4 m/s to the right collides with a 3 kg car moving to the left with a veloc

ity of 2 m/s. After the collision, the 6kg car continues forward with a velocity of 1 m/s. What is the new velocity of the 3 kg car after the collision?
Physics
1 answer:
sammy [17]2 years ago
8 0

Remember that moment before collision is equal to the moment after collision.

(m1 \times u1) + (m2 \times u2) = (m1 \times v1) + (m2  \times u2)

Plugging in our values,

(6 \times 4) - (3 \times 2) = (6 \times 1) + (3 \times v2) \\ 24 - 6 = 6 \times 3v2 \\ 18 = 18v2 \\ v2 = 1 {ms}^{ - 1}

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A 10 kg ball is held above a building with a height of 30 m. What is the
Darina [25.2K]

Answer: 2940 J

Explanation: solution attached:

PE= mgh

Substitute the values:

PE= 10kg x 9.8 m/s² x 30 m

= 2940 J

6 0
3 years ago
an airplane is traveling at an altitude of 31,360. a box of supplies is driped from the cargo hold how long will it take to reac
VMariaS [17]

Answer: 1,600 seconds

Explanation:

31,360/9.8 = 3,200.

Then divide 3,200/2 = 1,600

7 0
3 years ago
A human being can be electrocuted if a current as small as 51.0 ma passes near the heart. an electrician working with sweaty han
boyakko [2]

The fatal current is 51 mA = 0.051 Ampere.

The resistance is 2,050Ω .

Voltage = (current) x (resistance)

            =  (0.051 Ampere) x (2,050 Ω)  =  104.6 volts .

==================

This is what the arithmetic says IF the information in the question
is correct.

I don't know how true this is, and I certainly don't plan to test it,
but I have read that a current as small as  15 mA  through the
heart can be fatal, not  51 mA .

If 15 mA can do it, and the sweaty electrician's resistance is
really 2,050 Ω, then the fatal voltage could be as little as  31 volts !

The voltage at the wall-outlets in your house is  120 volts in the USA !
THAT's why you don't want to stick paper clips or a screwdriver into
outlets, and why you want to cover unused outlets with plastic plugs
if there are babies crawling around.
6 0
3 years ago
20 points and brainliest‼️‼️‼️‼️
Anastasy [175]

Answer:

0 N

Explanation:

Applying,

F = qvBsin∅................. Equation 1

Where F = Force on the charge, q = charge, v = Velocity, B = magnetic charge, ∅ = angle between the velocity and the magnetic field.

From the question,

Given: q = 4.88×10⁻⁶ C, v = 265 m/s, B = 0.0579 T, ∅ = 0°

Substitute these values into equation 1

F = ( 4.88×10⁻⁶)(265)(0.0579)(sin0)

Since sin0° = 0,

Therefore,

F = 0 N

3 0
3 years ago
Determine tge energy in joules of a photon whose frequency is 3.55x10
JulijaS [17]
E = hf
E = 6.63×10^-34 × 3.55×10 eV
1 eV = 1.60×10^-19 J
E = 6.63×10^-34 × 3.55×10 × 1.60×10^-19
E = 3.77×10^-51 J

Hope it helped!
6 0
3 years ago
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