Question

Ohm's Law for electrical circuits is stated Vequals​RI, where V is a constant​ voltage, R is the resistance in ohms and I is the current in amperes. Your firm has been asked to supply the resistors for a circuit in which V will be 9 volts and I is to be 5 plus or minus 0.1 amperes. In what interval does R have to lie for I to be within 0.1 amps of the target value Upper I 0 equals 5 question mark

Answer 1

Answer:

The resistance interval is  $R = 1.8 \pm 0.037$

Explanation:

From the question we are told that

     The voltage is  V  =  9 V

      The current is  $I = 5 \pm 0.1$

The maximum current would be  

       $I_{max} = 5 + 0.1 = 5.1 \ A$

The minimum current would be  

      $I_{min} = 5 - 0.1 = 4.9 \ A$

The maximum resistance is  

      $R_max = \frac{V}{I_{min}}$

     $R_max = \frac{9}{4.9}$

     $R_max = 1.837 \Omega$

The minimum resistance is  

      $R_{min} = \frac{V}{I_{max}}$

    $R_{min} = \frac{9}{5.1}$

    $R_{min} = 1.765 \Omega$

and  $R = \frac{9}{5} = 1.8 \Omega$

The  interval R  lies is  

        $R = 1.8 \pm 0.037$