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AlekseyPX
4 years ago
12

What is 4 1/2 - 1 3/4?

Mathematics
2 answers:
solniwko [45]4 years ago
8 0
The answer would be 11/4
ValentinkaMS [17]4 years ago
7 0
The answer would be 11/4
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What is 0.3636... round to the nearest tenth?
miskamm [114]
0.36. 
tenth position is b in . 0.ab
6 0
4 years ago
How do you find the area of a cube measuring 3ft it has 7sides
RUDIKE [14]
3 times 7= 21 times three =63

4 0
3 years ago
If f (x) = 5 x minus 25 and g (x) = one-fifth x + 5, which expression could be used to verify g(x) is the inverse of f(x)?
Vinil7 [7]

Answer:

The expression used to represent g(x) as inverse of f(x) is \frac{1}{5}(5x-25)+5

Option B is correct.

Step-by-step explanation:

We are given:

f(x)= 5x-25\\g(x)=\frac{1}{5}x+5

We need to find the expression that could be used to verify g(x) is the inverse of f(x).

We know that g(f(x))=x is inverse of function

So placing value of f(x) in g(x)

g(f(x))=\frac{1}{5}(5x-25)+5

So, the expression used to represent g(x) as inverse of f(x) is \frac{1}{5}(5x-25)+5

Option B is correct.

We can also solve to prove that g(f(x))=x

g(f(x))=\frac{1}{5}(5x-25)+5\\g(f(x))=\frac{5}{5}(x-5)+5\\g(f(x))=x-5+5\\g(f(x))=x

5 0
3 years ago
Read 2 more answers
45 mi<br> 28 mi<br> What is the length of the hypotenuse?
solniwko [45]

Answer:

c = 53 miles

Step-by-step explanation:

6 0
3 years ago
A rectangular area is to be fenced in with 300 feet of chicken wire. find the maximum area that can be enclosed.
GarryVolchara [31]
Let the lengths of the sides of the rectangle be x and y. Then A(Area) = xy and 2(x+y)=300. You can use substitution to make one equation that gives A in terms of either x or y instead of both.

2(x+y) = 300
x+y = 150
y = 150-x

A=x(150-x) <--(substitution)

The resulting equation is a quadratic equation that is concave down, so it has an absolute maximum. The x value of this maximum is going to be halfway between the zeroes of the function. The zeroes of the function can be found by setting A equal to 0:
0=x(150-x)
x=0, 150

So halfway between the zeroes is 75. Plug this into the quadratic equation to find the maximum area.

A=75(150-75)
A=75*75
A=5625

So the maximum area that can be enclosed is 5625 square feet.
6 0
3 years ago
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