Answer:
B) 20N.s is the correct answer
Explanation:
The formula for the impulse is given as:
Impulse = change in momentum
Impulse = mass × change in speed
Impulse = m × ΔV
Given:
initial speed = 40m/s
Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)
mass = 0.20 kg
Thus, we have
Impulse = 0.20 × (40m/s - (-60)m/s)
Impulse = 0.20 × 100 = 20 kg-m/s or 20 N.s
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The speed of the mass : <em><u>v = 0.316 m/s</u></em>
<h3>Further explanation</h3>
The energy used to press a spring is included as the potential energy
Can be formulated:
Ep= potential energy
k = spring constant
x = change in spring length
If the spring is released from its pressure, this potential energy will turn into kinetic energy
so applies the law of conservation of mechanical energy (Em)
Ek = Ep
A mass of 2 kg is attached to a spring, a spring constant of 20 N/m, and the spring is compressed 0.1 m past its natural length.
m = 2 kg
k = 20 N/m
x = 0.1 m
<h3>Learn more</h3>
Hooke's law
brainly.com/question/2648431
Keywords : spring,mass, spring constant,compressed position
Answer:
Explanation:
Given that,
Mass of first car
M1= 328kg
The car is moving in positive direction of x axis with velocity
U1 = 19.1m/s
Velocity of second car
U2 = 13m/s, in the same direction as the first car..
Mass of second car
M2 = 790kg
Velocity of second car after collision
V2 = 15.1 m/s
Velocity of first car after collision
V1 =?
This is an elastic collision,
And using the conservation of momentum principle
Momentum before collision is equal to momentum after collision
P(before) = P(after)
M1•U1 + M2•U2 = M1•V1 + M2•V2
328 × 19.1 + 790 × 13 = 328 × V1 + 790 × 15.1
16534.8 = 328•V1 + 11929
328•V1 = 16534.8—11929
328•V1 = 4605.8
V1 = 4605.8/328
V1 = 14.04 m/s
The velocity of the first car after collision is 14.04 m/s
After putting stuff through google and some calculators, I’d say the answer is C.
