Answer:
Example 1, if a vernier caliper output a measurement reading of 2.13 cm, this means that: The main scale contributes the main number(s) and one decimal place to the reading
E.g. 2. 1 cm, whereby 2 is the main number and 0.1 is the one decimal place number
Explanation:
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Scientists use models to study atoms, Because atoms are very tiny, and almost impossible to cut open and look inside.. And the center of an atom is the nucleus and that is ever smaller.
Answer:
a) F=20287.22N
b) t=2*10^-4s
Explanation:
E=1/2*m*v^2=0.5*7.8*10^-3kg*(530m/s)^2=1095.51J
The frictional force's work must be equal than the energy to stop the bullet.
So: W=F*d=F*0.054m=1095.51J, F=20287.22N
Considering the frictional force is constant, the bullet moves with constant aceleration.
a=F/m=20287.22N/7.8*10-2kg=2.6*10^6m/s^2
then d(t)=Vt-1/2*a*t^2,
5.4*10^-2m=530m/s*t-1.3*10^6m/s^2*t^2
I will calculate the time using the cuadratic formula:
with a=1.3*10^6, b=-530, c=5.4*10^-2
t=2*10^-4s
The force due to gravity on a 41.63 kg object would be 408.39 N.
<h3>What is gravity?</h3>
It can be defined as the force by which a body attracts another body towards its center as the result of the gravitational pull of one body and another,
The gravity varies according to the mass and size of the body for example the force of gravity on the moon is 1/6th times the force of gravity on the earth.
As given in the problem we have to calculate the force due to gravity on a 41.63 kg object.
Force= mass ×acceleration
The acceleration due to the gravity of the earth is 9.81 m/s²
Force = 41.63 ×9.81 N
= 408.39 N
Thus, the force because of the gravity on a 41.63- kg object comes out to be 408.39 N.
Learn more about gravity from here,
brainly.com/question/4014727
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Answer:
t = 12.6 seconds
Explanation:
Given that,
Initial velocity, u = 0
Acceleration of an electric vehicle, a = 2.3 m/s²
Final velocity, v = 29 m/s
We need to find the time elapses from start to stop. The acceleration of an object is given by the relation as follows :
So, 12.6 seconds is elapsed from start to stop.
