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cricket20 [7]
3 years ago
8

A cell phone charger operates at 5 volts and can deliver a maximum current of 1.0 Amp. If your cell phone has an energy storage

capacity of 38.9~38.9 kiloJoules, what is the shortest possible time (in hours) it would take to fully charge your empty phone battery using this charger.
Physics
1 answer:
madam [21]3 years ago
7 0

Answer:

<em>it</em><em> </em><em>takes</em><em> </em><em>2</em><em>.</em><em>1</em><em>6</em><em> </em><em>hrs</em><em> </em><em>to</em><em> </em><em>fully</em><em> </em><em>charge</em><em> </em><em>the</em><em> </em><em>phone</em>

Explanation:

V = 5v

I = 1A

E = 38.9 Kj = 38900 j

t = ?

E = IVt

t = E/IV

t = 38900 ÷ (1 × 5)

t = 38900 ÷ 5

t = 7780 seconds

t = 7780/3600............( converting time in seconds to hours)

t = 2.16 hrs

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I Explain why you feel cold when tap or well water in winter. state with reason.<br><br>​
attashe74 [19]

Answer:

We feel cold when tap or well water in winter because heat flows from hot body to cold body.

Explanation:

Our <em>body</em><em> </em><em>is</em><em> </em><em>in</em><em> </em><em>optimal</em><em> </em><em>status</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>hot</em><em> </em><em>body</em><em> </em><em>and</em><em> </em><em>tap</em><em> </em><em>or</em><em> </em><em>we</em><em>ll</em><em> </em><em>water</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>cold</em><em> </em><em>body</em><em>.</em><em> </em><em>Theref</em><em>ore</em><em> </em><em>we</em><em> </em><em>feel</em><em> </em><em>cold</em><em>.</em>

3 0
2 years ago
A triangular plate with height 6 ft and a base of 7 ft is submerged vertically in water so that the top is 2 ft below the surfac
xenn [34]

Answer:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)  } \, dy = 7875 lb

Explanation:

For this problem to be easier to calculate, we can represent the triangle as a right triangle whose right angle is located at the origin of a coordinate system. (See picture attached).

With this disposition of the triangle, we can start finding our integral. The hydrostatic force can be set as an integral with the following shape:

\int\limits^a_bγhxdy

we know that γ=62.5 lb/ft^{3}

from the drawing, we can determine the height (or depth under the water) of each differential area is given by:

h=8-y

x can be found by getting the equation of the line, which we'll get by finding the slope of the line and using one of the points to complete the equation:

m=\frac{y_{2}-y_{1}}{x_{2}-x{1}}

when substituting the x and y-values given on the graph, we get that the slope is:

m=\frac{0-6}{7-0}=-\frac{6}{7}

once we got this slope, we can substitute it in the point-slope form of the equation:

y_{2}-y_{1}=m(x_{2}-x_{1})

which yields:

y-6=-\frac{6}{7}(x-0)

which simplifies to:

y-6=-\frac{6}{7}x

we can now solve this equation for x, so we get that:

x=-\frac{7}{6}y+7

with this last equation, we can substitute everything into our integral, so it will now look like this:

\int\limits^6_0{(62.5)(8-y)(-\frac{7}{6}y+7)}\,dy

Now that it's all written in terms of y we can now simplify it, so we get:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)}dy

we can now proceed and evaluate it.

When using the power rule on each of the terms, we get the integral to be:

62.5[\frac{7}{18}y^{3}-\frac{49}{6}y^{2}+56y]^{6}_{0}

By using the fundamental theorem of calculus we get:

62.5[(\frac{7}{18}(6)^{3}-\frac{49}{6}(6)^{2}+56(6))-(\frac{7}{18}(0)^{3}-\frac{49}{6}(0)^{2}+56(0))]

When solving we get:

62.5\int\limits^6_0 {(\frac{7}{6}y^{2}-\frac{49}{3}y+56)  } \, dy = 7875 lb

6 0
3 years ago
Calculating heat gained or lost requires mass, specific heat, and
Anarel [89]
<span>Calculating heat gained or lost requires mass, specific heat, and

</span><span>c. change in temperature.</span><span>

</span>
6 0
3 years ago
At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in
bearhunter [10]

Answer:

P = 1.09 \times 10^8 Pa

Explanation:

As we know that the pressure inside the liquid level is given as

P = \rho g h + P_o

here we have

\rho = 1024 kg/m^3

h = 10.9 km

also we know that

P_o = 1.01 \times 10^5 Pa

now we have

P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)

P = 1.09 \times 10^8 Pa

8 0
3 years ago
Qual o valor a ser pago, no final de 5 meses e 18 dias, correspondente a um empréstimo de $125.000,00, sabendo-se que a taxa de
liberstina [14]
25% ao semestre = 25%/6 ao mes.
Um mes tem em media 365/12 dias, ou 30,42 dias/mes.
18 dias = 18/30,42 mes

5 meses + 18 dias = 5 meses + 18/30,42 mes = 5,592 mes

a taxa de juros por 5 meses e 18 dias e 25%/6 * 5.592 = 23,3%

123,3% * $125.000 = $154.125,00
6 0
4 years ago
Read 2 more answers
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