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Sindrei [870]
3 years ago
15

Calculate the inhomogeneity of a 1.5 t magnet

Physics
1 answer:
Ludmilka [50]3 years ago
6 0
Need more answer choices
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An electric travel blanket uses a car's 12V supply. The current is 3A.
snow_lady [41]

For electrical devices . . .

           Power dissipated = (voltage) x (current) =

                                             (12 V)  x  (3.0 A) = 36 watts .

1 watt means 1 joule per second

           (36 joule/sec) x (60 sec/min) x (10 min)  =  21,600 joules

5 0
3 years ago
A 25 N force stretches a spring 280 cm. What was the spring constant? ​
boyakko [2]

Answer:

  1. F= 25N
  2. ∆l=280cm
  3. K=?
  4. you apply the formula = K:F/∆l
  5. = 0,089N/cm
4 0
3 years ago
Read 2 more answers
A psychopathologist records the number of criminal offenses among teenage drug users in a nationwide sample of 1,201 participant
lara [203]

Answer:

Standard deviation = 3

Explanation:

Given

N = 1201

SS = 10800

Required

Determine the standard deviation

First, we need to determine the variance;

Variance = \frac{SS}{N - 1}

This gives:

Variance = \frac{10800}{1201 - 1}

Variance = \frac{10800}{1200}

Variance = 9

Know that:

Variance = SD^2

Where SD represents standard deviation

This gives

9 = SD^2

Take square root

SD = \sqrt 9

SD = 3

7 0
3 years ago
What is the difference between a graph of linear motion and a graph of harmonic motion?
fredd [130]
Hope this helps :)

When describing linear motion, you need only one graph representing each of the three terms, while projectile motion requires a graph of the x and y axes. Graphs of simple harmonic motion are sine curves. Circular motion is different from other forms of motion because the speed of the object is constant.
5 0
3 years ago
Whats the answer???????????
Leviafan [203]

Answer: Less than 4 ohms

Explanation:

We have three resistors with the following resistance:

R_{1}=4\Omega

R_{2}=6\Omega

R_{3}=8\Omega

Now, when the resistors are connected in parallel, the total resistance R is calculated as follows:

\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}

Isolating R:

R=\frac{R_{1}R_{2}R_{3}}{R_{3}(R_{1}+R_{2})+R_{1}R_{2}}

Rewriting with th known values:

R=\frac{(4\Omega)(6\Omega)(8\Omega)}{8\Omega(4\Omega+6\Omega)+(4\Omega)(6\Omega)}

Finally:

R=1.84 \Omega

Hence, the correct option is less than 4 ohms.

4 0
3 years ago
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