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Brrunno [24]
3 years ago
12

Whats 4 square root of 1296

Mathematics
1 answer:
Katen [24]3 years ago
4 0
The square root of 1296 is 6.


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PLEASE HELP ME THANK YOU
Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

That exterior angle of 111 is equal to the sum of the triangle's remote interior angles. We add the 37 + 35 to get a total angle measure of 72. That means that the base angle on the right is 111 - 72 = 39. That 39 degree angle is vertical to x; that means that x = 39 as well.

3 0
3 years ago
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What do the following two equations represent?
noname [10]

Answer:

It parallel line.

Step-by-step explanation:

7 0
3 years ago
Please help! im struggling
ANEK [815]
3. x=0 y= 3
4. x=-2 y=3
8 0
3 years ago
Given f (x ) = x^2 + 3x + 2 and g (x ) = x + 1, perform the indicated operations.
Nana76 [90]

Answer:

(i) (f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = x³ + 4·x² + 5·x + 2

Step-by-step explanation:

The given functions are;

f(x) = x² + 3·x + 2

g(x) = x + 1

(i) (f - g)(x) = f(x) - g(x)

∴ (f - g)(x) = x² + 3·x + 2 - (x + 1) = x² + 3·x + 2 - x - 1 = x² + 2·x + 1

(f - g)(x) = x² + 2·x + 1

(ii) (f + g)(x) = f(x) + g(x)

∴ (f + g)(x) = x² + 3·x + 2 + (x + 1) = x² + 3·x + 2 + x + 1 = x² + 4·x + 3

(f + g)(x) = x² + 4·x + 3

(iii) (f·g)(x) = f(x) × g(x)

∴ (f·g)(x) = (x² + 3·x + 2) × (x + 1) = x³ + 3·x² + 2·x + x² + 3·x + 2 = x³ + 4·x² + 5·x + 2

(f·g)(x) = x³ + 4·x² + 5·x + 2

7 0
3 years ago
Rule for raising a power to a new power
KiRa [710]
The practical rule would be, times that number, by the result of the first time you multiplied the first number. But, it would all depend by how much your're raising the number by.

<u>For example:</u> \boxed{4^6}

We do, (4*4*4*4*4*4)= \boxed{\bf{4^6}}= 4096

But, once again, this was an example. This would show and illustrate the rule of "raising a power".<span />
5 0
4 years ago
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