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IrinaK [193]
3 years ago
12

What is the eccentricity of mercury

Chemistry
2 answers:
suter [353]3 years ago
6 0
According to my astronomy book, it's about 0.206
Tanzania [10]3 years ago
5 0
It's eccentricity is about 0.21
You might be interested in
Due tonight! Please help!
olchik [2.2K]

Answer:

42.98 g/L

Explanation:

6 0
3 years ago
Which particle diagram represents a mixture of three substances
Anni [7]

Following the key in the diagram (see the attached image), the only particle diagram that represents a mixture of three substances is diagram 2.

To simplify it, let us replace the key in the diagram as follows;

  1. atom of one element = A
  2. atom of different element = B

Diagram 1 consists of only AA and AB

Diagram 2 consists of AA, BB, and AB.

Diagram 3 consists of AA and ABA

Diagram 4 consists of AA and BAB

Thus, only diagram 2 has a mixture of 3 substances.

More on mixtures can be found here: brainly.com/question/6594631

4 0
2 years ago
Calculate the density for a rectangular block using the following measurements: Length = 10 cm, Width = 1.1 cm, Height = 15 cm,
Ksivusya [100]

Answer:

0.40 g/cm3

Explanation:

density = mass / volume.

mass = 65.2 grams

volume = 10*1.1*15=165 cm3

so density = 65.2/165=0.40 g/cm3

3 0
2 years ago
Question 1:
Alona [7]

Question 1:

(a) Sulfurous acid: H2SO3

Sulfuric acid: H2SO4

(b) Nitrous acid: H2NO2

Nitric acid: H2NO3

Question 2:

To calculate the pH, based on concentration of H+ ions, there is one formula:

ph =   - log_{10}(c(h + ))

So the pH of this solution is

-  log_{10}( {10}^{ - 9} )  = 9

(the solution is basic).

5 0
2 years ago
A first-order reaction is 45% complete at the end of 43 minutes. What is the length of the half-life of this reaction
shtirl [24]

The half-life of the reaction is 50 minutes

Data;

  • Time = 43 minutes
  • Type of reaction = first order
  • Amount of Completion = 45%

<h3>Reaction Constant</h3>

Let the initial concentration of the reaction be X_0

The reactant left = (1 - 0.45) X_0 = 0.55 X_0 = X

For a first order reaction

\ln(\frac{x}{x_o}) = -kt\\ k = \frac{1}{t}\ln (\frac{x_o}{x}) \\ k = \frac{1}{43}\ln (\frac{x_o}{0.55_o})\\ k = 0.013903 min^-^1

<h3>Half Life </h3>

The half-life of a reaction is said to be the time required for the initial amount of the reactant to reach half it's original size.

x = \frac{x_o}{2} \\t = t_\frac{1}{2} \\t_\frac{1}{2} = \frac{1}{k}\ln(\frac{x_o}{x_o/2})\\

Substitute the values

t_\frac{1}{2} = \frac{1}{k}\ln(2)=\frac{0.6931}{0.013903}\\t_\frac{1}{2}= 49.85 min = 50 min

The half-life of the reaction is 50 minutes

Learn more on half-life of a first order reaction here;

brainly.com/question/14936355

4 0
2 years ago
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