Answer:
Option D. w1[x] w2[u] w2[y] w1[y] w3[x] w3[u] w1[z]
Explanation:
The execution in the option D is correct. This is because there is more than one reasonable criterion.
Answer:
γ
=0.01, P=248 kN
Explanation:
Given Data:
displacement = 2mm ;
height = 200mm ;
l = 400mm ;
w = 100 ;
G = 620 MPa = 620 N//mm²; 1MPa = 1N//mm²
a. Average Shear Strain:
The average shear strain can be determined by dividing the total displacement of plate by height
γ
= displacement / total height
= 2/200 = 0.01
b. Force P on upper plate:
Now, as we know that force per unit area equals to stress
τ = P/A
Also, τ = Gγ
By comapring both equations, we get
P/A = Gγ
------------ eq(1)
First we need to calculate total area,
A = l*w = 400 * 100= 4*10^4mm²
By putting the values in equation 1, we get
P/40000 = 620 * 0.01
P = 248000 N or 2.48 *10^5 N or 248 kN
Watts I believe is the answer
Answer:
Cost = $2527.2 per month.
Explanation:
Given that
Discharge ,Q = 130 L/min
So

Cost = $0.45 per cubic meter
1 month = 30 days
1 days = 24 hr = 24 x 60 min
1 month = 30 x 24 x 60 min
1 month = 43,200 min
Lets x
x = 0.13 x 43,200

So the total cost = 5616 x 045 $
Cost = $2527.2 per month.