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Oksanka [162]
3 years ago
5

Tahir travel twice as far as ahmed, but onley one third as fast. Ahmed starts travel on tuesday at noon at point x to point z 30

0km, by 9:00pm. Tahir starts travel same day after 3hr of ahmed. In which time tahir reach at point z?
Engineering
1 answer:
shepuryov [24]3 years ago
7 0

Answer:

6:00 pm the next day

Explanation:

Given that

Tahir traveled twice as far as Ahmed. We say,

Ahmed traveled a distance, D

Tahir would travel a distan, 2D

Tahir traveled 1/3 as fast as Ahmed, so we say

Ahmed traveled at a speed, S

Tahir would travel at a speed, S/3

If Ahmed starts travel on tuesday at noon at point x to point z 300km, by 9:00pm,

Time taken by Ahmed to travel is

9:00 pm - 12:00 pm = 9 hours

Ahmed, traveled 300 km in 9 hours, meaning he traveled at 33.3 km in an hour.

Speed, S that Ahmed traveled with is 33.3 km/h

Remember, we stated that Tahir travels at a speed of S/3, that is, The speed of Tahir is

33.3/3 = 11.1 km/h.

300 km would then be traveled in 300 km/11.1 km/h = 27 hours.

Tahir started traveling, 3 hours after Ahmed, that is 12:00 pm + 3:00 hrs = 3:00 pm, and if he's to spend 27 hours on the journey he would reach destination z at 6:00 pm the next day

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Answer: 9.9KJ

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Heat into system is 10kJ = 10000KJ

Therefore

U = Q - W - losses

U = 10000 - 2 - 80 = 9990J

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Answer:

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Explanation:

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3 years ago
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Ronch [10]

Answer:

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Explanation:

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The friction between the two surfaces, converts the kinetic energy of the movement to the thermal energy.

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7 0
3 years ago
A closed system consisting of 4 lb of a gas undergoes a process during which the relation between pressure and volume is pVn 5 c
gayaneshka [121]

Answer:

V1=5<u>ft3</u>

<u>V2=2ft3</u>

n=1.377

Explanation:

PART A:

the volume of each state is obtained by multiplying the mass by the specific volume in each state

V=volume

v=especific volume

m=mass

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V1=m.v1

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state 2

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PART B:

since the PV ^ n is constant we can equal the equations of state 1 and state 2

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3 years ago
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