Answer:
Relative density = 0.545
Degree of saturation = 24.77%
Explanation:
Data provided in the question:
Water content, w = 5%
Bulk unit weight = 18.0 kN/m³
Void ratio in the densest state, 
= 0.51
Void ratio in the loosest state, 
= 0.87
Now,
Dry density, 
= 17.14 kN/m³
Also,
here, G = Specific gravity = 2.7 for sand
or
e = 0.545
Relative density = 
= 
= 0.902
Also,
Se = wG
here,
S is the degree of saturation
therefore,
S(0.545) = (0.05)()2.7
or
S = 0.2477
or
S = 0.2477 × 100% = 24.77%
if a pilot-operated check valve (POC) does not check flow, you will see The symptoms and symptoms of a failing swing test valve are regularly audible.
<h3>
What happens when the pilot valve reaches set strain?</h3>
When the pilot valve reaches set strain it opens and releases the strain from the dome. The piston is then unfastened to open and the principle valve exhausts the machine fluid. The manage pilot opens both to the principle valve exhaust pipe or to the atmosphere.
Pilot operated test valves paintings through permitting unfastened go with the drift from the inlet port thru the opening port. Supplying a pilot strain to the pilot port permits go with the drift withinside the contrary direction. Air strain on the pinnacle of the poppet meeting opens the seal permitting air to go with the drift freely.
Read more about the pilot valve :
brainly.com/question/15565472
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Answer:
(b) kcal/kg
Explanation:
CALORIFIC VALUE : Calorific value is measured in units of energy per unit substances its unit may be kcal/kg, cal/kg ,kcal/mol as the mole is also unit of measurements of substance present another unit may be cal/mol
So the unit of the calorific value will be kcal/kg because kcal is unit of energy and kg is unit of substance present so option (b) will be the correct option
