The flatbed truck carries a large section of circular pipe secured only by the two fixed blocks A and B of height h. The truck i
2 answers:
Answer:
The maximum speed for which the pipe will be restrained is 18.05 m/s.
Explanation:
We note that the
Securing blocks have height, h = 0.1 m
The radius of travel, rho = 60 m
The radius of the circular pipe, R = 0.8 m
We note that the weight of the pipe is acting at the centroid of the pipe
Therefore, for the pipe to slip, it has to climb the wedge h
Taking moments about h, we have
mg × R sin α = ma × R cos α
a/g = Tan α
But a =
Therefore = g tanα
Since height of the block, h = 0.1 m therefore,
R cos α = R - h
That is 0.8 cos α = 0.8 - 0.1 = 0.7
Therefore α = cos⁻¹ (0.7/0.8) = 28.96 °
From which V² = rho × g× tanα = 60 × 9.81 × tan 28.96
= 325.66 m²/s²
∴ V = √(325.66 m²/s²) = 18.05 m/s
Maximum speed = 18.05 m/s.
Answer:
The maximum speed is 18.1 m/s
Explanation:
the angle made by the line of action of reaction forces and normal reaction with the center is equal to:
If R=0.8 m and h=0.1 m, we have:
the equilibrium of forces acting in y-direction is zero and we have the following:
Clearing RB:
where RB is reaction force on the ring and m is the mass of circular ring
the equilibrium of forces acting in n-direction is equal to:
where p is the radius and v is the speed. if RB=mg/cosα
Replacing values:
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Answer:
a)
b)
c)
d)
Explanation:
Non horizontal pipe diameter, d = 25 cm = 0.25 m
Radius, r = 0.25/2 = 0.125 m
Entry temperature, T₁ = 304 + 273 = 577 K
Exit temperature, T₂ = 284 + 273 = 557 K
Ambient temperature,
Pipe length, L = 10 m
Area, A = 2πrL
A = 2π * 0.125 * 10
A = 7.855 m²
Mass flow rate,
Rate of heat transfer,
a) To calculate the convection coefficient relationship for heat transfer by convection:
Note that we cannot calculate the heat loss by the pipe to the environment without first calculating the surface temperature of the pipe.
c) The surface temperature of the pipe:
Smear coefficient of the pipe,
b) Heat loss from the pipe to the environment:
d) The required fan control power is 25.125 W as calculated earlier above
Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void insert(int* arr, int* size, int value, int position){
if(position<0 || position>=*size){
cout<<"position is greater than size of the array"<<endl;
return ;
}
*size = *size + 1 ;
for(int i=*size;i>position;i--){
arr[i] = arr[i-1];
}
arr[position] = value ;
}
void print(int arr[], int size){
for(int i=0;i<size;i++){
cout<< arr[i] <<" ";
}
cout<<" "<<endl;
}
void remove(int* arr, int* size, int position){
* size = * size - 1 ;
for(int i=position;i<*size;i++){
arr[i] = arr[i+1];
}
}
int count(int arr[], int size, int target){
int total = 0 ;
for(int i=0;i<size;i++){
if(arr[i] == target)
total += 1 ;
}
return total ;
}
int main()
{
int size;
cout<<"Enter the initial size of the array:";
cin>>size;
int arr[size],val;
cout<<"Enter the values to fill the array:"<<endl;
for(int i=0;i<size;i++){
cin>>val;
arr[i] = val ;
}
int choice = 5,value,position,target ;
do{
cout<<"Make a selection:"<<endl;
cout<<"1) Insert"<<endl;
cout<<"2) Remove"<<endl;
cout<<"3) Count"<<endl;
cout<<"4) Print"<<endl;
cout<<"5) Exit"<<endl;
cout<<"Choice:";
cin>>choice;
switch(choice){
case 1:
cout << "Enter the value:";
cin>>value;
cout << "Enter the position:";
cin>>position;
insert(arr,&size,value,position);
break;
case 2:
cout << "Enter the position:";
cin>>position;
remove(arr,&size,position);
break;
case 3:
cout<<"Enter the target value:";
cin>>target;
cout <<"The number of times "<<target<<" occured in your array is:" <<count(arr,size,target)<<endl;
break;
case 4:
print(arr,size);
break;
case 5:
cout <<"Thank you..."<<endl;
break;
default:
cout << "Invalid choice..."<<endl;
}
}while(choice!=5);
return 0;
}
Kindly check the attached images below for the code output.
