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dexar [7]
2 years ago
6

Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equ

ation)
Chemistry
1 answer:
DedPeter [7]2 years ago
5 0

Answer:

Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu

Explanation:

  • Solid Iron = Fe
  • Copper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).
  • Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)
  • Metal Copper = Cu

Writing the equation using symbols leaves us with:

  • Fe + CuNO₃ → Fe(NO₃)₃ + Cu

<em>It is not balanced yet</em>. Now we <u>balance the NO₃ species on the left side</u>:

  • Fe + 3CuNO₃ → Fe(NO₃)₃ + Cu

Finally we<u> balance the Cu species on the right side</u>:

  • Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
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<u>Answer:</u> The de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

<u>Explanation:</u>

Kinetic energy is the measure of temperature of the system.

The equation used to calculate kinetic energy of a particle follows:

E=\frac{3}{2}kT

where,

E = kinetic energy of the particles  = ?

k = Boltzmann constant  = 1.38\times 10^{-23}J/K

T = temperature of the particle = 30 K

Putting values in above equation, we get:

E=\frac{3}{2}\times 1.38\times 10^{-23}J/K\times 30K\\\\E=6.21\times 10^{-22}J

  • Calculating the mass of 1 molecule of hydrogen gas:

Conversion factor used:  1 kg = 1000 g

1 mole of hydrogen gas has a mass of 2 grams or 2\times 10^{-3}kg  

According to mole concept:

6.022\times 10^{23} number of molecules occupy 1 mole of a gas.

As, 6.022\times 10^{23} number of hydrogen molecules has a mass of 2\times 10^{-3}kg

So, 1 molecule of hydrogen will have a mass of = \frac{2\times 10^{-3}kg}{6.022\times 10^{23}}\times 1=3.32\times 10^{-27}kg

  • To calculate the wavelength of a particle, we use the equation given by De-Broglie's wavelength, which is:

\lambda=\frac{h}{\sqrt{2mE_k}}

where,

\lambda = De-Broglie's wavelength = ?

h = Planck's constant = 6.624\times 10^{-34}Js

m = mass of 1 hydrogen molecule = 3.32\times 10^{-27}kg

E_k = kinetic energy of the particle = 6.21\times 10^{-22}J

Putting values in above equation, we get:

\lambda=\frac{6.624\times 10^{-34}Js}{\sqrt{2\times 3.32\times 10^{-27}kg\times 6.21\times 10^{-22}J}}

\lambda=3.26\times 10^{-10}m=3.26\AA    (Conversion factor: 1\AA=10^{-10}m )

Hence, the de-Broglie's wavelength of a hydrogen molecule is 3.26\AA

3 0
3 years ago
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allochka39001 [22]

Answer: The correct answer is D. 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit.

Explanation:

Conversion of degree Celsius to Kelvin :

K=^oC+273

Conversion of degree Celsius to degrees Fahrenheit :

^oF=(\frac{9}{5}\times ^oC)+32

By using these two conversion factors, we get the three temperature readings all mean the same thing.

For option A :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option B :

K=^oC+273=100+273=373K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 100)+32=212^oF

For option C :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

For option D :

K=^oC+273=0+273=273K

^oF=(\frac{9}{5}\times ^oC)+32=(\frac{9}{5}\times 0)+32=32^oF

From the given options, only option (D) is correct.

Hence, the correct option is, (D) 273 Kelvin, 0 degrees Celsius, 32 degrees Fahrenheit

Hope this helps!

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Answer:

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Chemical changes are driven by change in chemical properties of matter.

In a school, iron components might begin to rust. This is a chemical change.

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