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UkoKoshka [18]
3 years ago
9

g In photosystem II, after pigment molecules donate excited electrons to the reaction center, electrons are taken from ___ to re

place them. A. sugar B. water C. sunlight D. carbon dioxide
Chemistry
1 answer:
marysya [2.9K]3 years ago
7 0

Answer: B(water)

Explanation:

Photosystem II uses energy from light to extract electron from water molecule to fill the hole left as the energized electron passes up the chain.When the electrons are removed from the water molecules,the water molecule breaks down into oxygen gas,which bubbles away, and hydrogen ions,which are used to power ATP synthesis.

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At the end of the last lesson, you learned there was not enough carbon dioxide in the biodome air, which led to a decrease in en
lakkis [162]

There may be too many plants present or too few animals in the biodome hence the decrease in carbon dioxide .

<h3>What is a biodome?</h3>

The term biodome refers to an artificially buit ecosystem. We must recall that an ecosystem is a self sustaining unit in which materials and energy are exchanged.

If there is less carbon dioxide in the biodome then it means that there are too many plants present or too few animals in the biodome.

Learn more about ecosystem: brainly.com/question/1673533

4 0
2 years ago
In acidic solution, the sulfate ion can be used to react with a number of metal ions. One such reaction is SO42−(aq)+Sn2+(aq)→H2
allsm [11]

Answer:

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

Explanation:

SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)

Balancing in acidic medium:

First we will determine the oxidation and reduction reaction from the givne reaction :

Oxidation:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)

Balance the charge by adding 2 electrons on product side:

Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)+2e^-....[1]

Reduction :

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)

Balance O by adding water on required side:

SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

Now, balance H by adding H^+ on the required side:

SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)

At last balance the charge by adding electrons on the side where positive charge is more:

SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)..[2]

Adding [1] and [2]:

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

The final balanced equation is :

SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)

4 0
2 years ago
Look at sample problem 19.10 in the 8th ed Silberberg book. Write the Ksp expression. Find the concentrations of the ions you ne
777dan777 [17]

Answer:

Explanation:

From the information given:

CaF_2 \to Ca^{2+} + 2F^-

Ksp = 3.2 \times 10^{-11}

no of moles of Ca^{2+} = 0.01 L × 0.0010 mol/L

no of moles of Ca^{2+} = 1 \times 10^{-5} \ mol

no of moles of F^- = 0.01 L × 0.00010 mol/L

no of moles of F^- = 1 \times 10^{-6}\ mol

Total volume = 0.02 L

[Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\  \\  \[[Ca^{2+}}] = 0.0005 \ mol/L

[F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}

[F^{-}] = 5 \times 10^{-5}  \ mol/L

Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}

Since Q<ksp, then there will no be any precipitation of CaF2

3 0
3 years ago
Avogrados number of representatives particles is equal to one what?​
kotykmax [81]

Answer:

Avogadro number of representatives particles is equal to one mole.

Explanation:

The number 6.022 × 10²³ is called Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

17 g of ammonia = 1 mole =  6.022 × 10²³ molecules of ammonia

12 g of carbon = 1 mole = 6.022 × 10²³ atoms of carbon

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

5 0
3 years ago
Is C2H6 empirical molecular or both
marshall27 [118]

Answer:

molecular

Explanation:

7 0
2 years ago
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