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makvit [3.9K]
3 years ago
15

A flask contains methane, chlorine and carbon monoxide gases. the partial pressures of each are 0.215 atm, 0.066 atm, and 0.826

atm, respectively. what is the total pressure in the flask in atm?
Chemistry
2 answers:
hjlf3 years ago
8 0

Answer;

The total pressure is 1.107 atm.

Explanation;

The total pressure is the sum of the pressures of the three gases in the flask

Pressure (total) = 0.215 atm + 0.066 atm + 0.826 atm = 1.107 atm

= 1.107 atm.

elixir [45]3 years ago
5 0

The law of partial pressures or Dalton's law, formulated the British chemist John Dalton in 1802, establishes that <u>the pressure of a mixture of gases</u>, that do not react chemically, <u>is equal to the sum of the partial pressures that each of them would exert if only one occupied the entire volume of the mixture</u>, without changing the temperature.

In this way, <u>Dalton's law can be used to determine the total pressure in a container that has a mixture of gases</u>, each of which exerts a partial pressure, considering that all gases behave like ideal gases.

According to Dalton's law, the total pressure in the flask will be,

P_{total} = P_{methane} + P_{chlorine} + P_{CO}

→ P_{total} = 0.215 atm + 0.066 atm + 0.826 atm

→ P_{total} = 1.107 atm

So, the total pressure in the flask is equal to 1.107 atm.

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siniylev [52]

Answer: Yes! you're all good. Alkali metals in group 1 are the most metallic :)

6 0
3 years ago
identify the reagents you would use to convert each of the following compounds into pentanoic acid: (a) 1-pentene (b) 1-bromobut
Morgarella [4.7K]

a)BH3.THF is used to convert 1-pentane to pentanoic acid and b)NaCN is used to convert Bromobutane to pentanoic acid.

a) The conversion of 1-pentane to pentanoic acid using BH3, also known as hydroboration-oxidation, is a two-step reaction involving the reaction of 1-pentane with borane (BH3), followed by oxidation of the resulting 1-pentylborane with hydrogen peroxide or other oxidizing agents.

In the first step, 1-pentane reacts with borane (BH3) to form 1-pentylborane, through a process known as hydroboration. This reaction is catalyzed by a Lewis acid, such as aluminum chloride, and proceeds via a hydride transfer from the borane to the 1-pentane.

In the second step, the 1-pentylborane is oxidized to pentanoic acid using hydrogen peroxide (H₂O₂) or other suitable oxidizing agents. The oxidation is catalyzed by an acid, such as hydrochloric acid (HCl), and proceeds via a proton transfer from the 1-pentylborane to the hydrogen peroxide. The end result is the conversion of 1-pentane to pentanoic acid.

The overall chemical reaction for the conversion of 1-pentane to pentanoic acid using borane (BH₃) and hydrogen peroxide (H₂O₂) is as follows:

1-pentane + BH₃ + H₂O₂ → pentanoic acid + H₂O + BH₂

b)The conversion of 1-Bromo butane to pentanoic acid using sodium cyanide (NaCN) proceeds via a nucleophilic substitution reaction. The reaction mechanism involves the following steps:

1. Attack of the nucleophile, NaCN, on the carbon atom of 1-Bromo butane to form a tetrahedral intermediate.

2. Loss of a proton from the tetrahedral intermediate to form a carbanion.

3. Protonation of the carbanion by water (or another proton source) to form pentanoic acid.

The overall reaction can be represented as follows:

1-Bromo butane + NaCN → Pentanoic Acid + NaBr

To know more about reagents, click below:

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3 0
1 year ago
Calculate the wavelength, in nanometers, of the spectral line produced when an electron in a hydrogen atom undergoes the transit
Lapatulllka [165]

<u>Answer:</u> The wavelength of spectral line is 656 nm

<u>Explanation:</u>

To calculate the wavelength of light, we use Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_f^2}-\frac{1}{n_i^2} \right )

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant  = 1.097\times 10^7m^{-1}

n_f = Final energy level = 2

n_i= Initial energy level = 3

Putting the values in above equation, we get:

\frac{1}{\lambda }=1.097\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.524\times 10^6m^{-1}}=6.56\times 10^{-7}m

Converting this into nanometers, we use the conversion factor:

1m=10^9nm

So, 6.56\times 10^{-7}m\times (\frac{10^9nm}{1m})=656nm

Hence, the wavelength of spectral line is 656 nm

6 0
3 years ago
Calculate the molarity of a solution that contains 0.250 moles of kf in 0.500 l of water
MakcuM [25]
Molarity can be defined as the number of moles of solute in 1 L of solution.

M = n/V

Where M is the molarity of the solution (M or mol/L), n is the moles of the solute (mol) and V is the volume of the solution (L).

Here, solute is KF.

n = <span>0.250 mol
</span>V = 0.500 L
M = ?

By applying the formula,
   M = 0.250 mol / 0.500 L
   M = 0.500 mol/L

Hence, the molarity of KF solution is 0.500 mol/L.

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3 years ago
Name the elements present of carbon monoxide
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