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makvit [3.9K]
3 years ago
15

A flask contains methane, chlorine and carbon monoxide gases. the partial pressures of each are 0.215 atm, 0.066 atm, and 0.826

atm, respectively. what is the total pressure in the flask in atm?
Chemistry
2 answers:
hjlf3 years ago
8 0

Answer;

The total pressure is 1.107 atm.

Explanation;

The total pressure is the sum of the pressures of the three gases in the flask

Pressure (total) = 0.215 atm + 0.066 atm + 0.826 atm = 1.107 atm

= 1.107 atm.

elixir [45]3 years ago
5 0

The law of partial pressures or Dalton's law, formulated the British chemist John Dalton in 1802, establishes that <u>the pressure of a mixture of gases</u>, that do not react chemically, <u>is equal to the sum of the partial pressures that each of them would exert if only one occupied the entire volume of the mixture</u>, without changing the temperature.

In this way, <u>Dalton's law can be used to determine the total pressure in a container that has a mixture of gases</u>, each of which exerts a partial pressure, considering that all gases behave like ideal gases.

According to Dalton's law, the total pressure in the flask will be,

P_{total} = P_{methane} + P_{chlorine} + P_{CO}

→ P_{total} = 0.215 atm + 0.066 atm + 0.826 atm

→ P_{total} = 1.107 atm

So, the total pressure in the flask is equal to 1.107 atm.

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A piece of mental with a mass of 106 g is placed in a 50 mL graduated cylinder.The volume rises from 20 mL to 31 mL. What is the
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9.64g/mL

Explanation:

Given parameters:

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Volume difference  = 31mL  - 20mL  = 11mL

Unknown:

Density of the metal  = ?

Solution:

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Octylphenol ethoxylate is a detergent that is commonly used in chemistry laboratories. It is a thick, yellowish liquid. A chemis
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Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of
bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol..[1]

O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol..[2]

NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol..[3]

NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}

2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol

2\times \Delta H^o_{4}=470.3 kJ/mol

\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0
3 years ago
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