The frequencies expressed in inverse seconds are 5 s⁻¹ and 1 s⁻¹.
<h3>
What is frequency?</h3>
Frequency is the number of complete cycles in a second made by a wave.
F = 1/T
F = n/t
<h3>When n = 5</h3>
F = 5/s = 5 s⁻¹ = 5Hz
<h3>When n = 1</h3>
F = 1/s = 1 s⁻¹ = 1Hz
Learn more about frequency here: brainly.com/question/254161
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948 or 9.48 x 10^2
There are two sets of rules for significant figures
• One set for addition and subtraction
• Another set for multiplication and division
You used the set for multiplication and division.
This problem involves addition and subtraction, and the rule is
The number of places after the decimal point in the answer must be <em>no greater than the number of decimal places in every term</em> in the sum.
Thus, we have
78.9
+890.43
-21.
= 948.33
The "21" term has the fewest digits after the decimal point (none), so the answer must have no digits after the decimal point.
To the correct answer is 948 = 9.48 x 10^2. It has three significant figures.
Answer:
Cl⁻ was oxidized.
Explanation:
- 4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂
Oxidation can be defined as the process in which the oxidation number of a substance increases.
On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.
Thus, Cl⁻ was oxidized.
Answer:
0.017mole
0.0033M
Explanation:
Given parameters:
Formula of the compound:
Mg(ClO₃)₂
Mass of the sample = 3.24g
Unknown:
Number of moles of the sample = ?
Molarity = ?
Solution:
The number of moles of any substance is given as:
Number of moles = 
Molar mass of Mg(ClO₃)₂ = 24 + 2[35.5 + 3(16)] = 191g/mol
Number of moles = 
= 0.017mole
Molarity is the number of moles of a solute in a solution:
Molarity = 
Volume given = 5.08L
Molarity = 
= 0.0033M
For the answer to the question above, asking to w<span>rite the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2)and You do not need to make the subscripts smaller.
My answer would be,
</span><span>4Al(s) + 3O2(g) --->2 Al2O3(s)
</span>
I hope this helps.
