Talia is packing a moving box. She has a square-framed poster with an area of 16 square feet. The

Mathematics

1 answer:

irakobra [83]3 years ago

7 0

Answer:

We calculate for the dimensions (the length of the sides) of both the poster and the cube. If the length of the side of the poster is shorter compared to that of the box then, the poster will lie flat in the cube. However, if the poster has a length that is longer than that of the cube then, it will not lie flat in the cube.

length of the poster = sqrt (9 ft^2) = 3 ft

length of the cube = cbrt (30 ft^3) = 3.11 ft

Since, the length of the cube is longer compared to the length of the poster then, the poster will lie flat on the cube

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Can you help me with this math il give you 100 points

abruzzese [7]

I'd he happy to, But you forgot to post the question.

8 0

2 years ago

The cross section of a parabolic reflector has a vertical axis of symmetry with its vertex at (0,0) . The focus of the reflector

Paha777 [63]

Answer:

The depth of the reflector is 0.84 feet

Step-by-step explanation:

<em>(See the figure below)</em>

The equation of a parabola centered at the origin with an axis of symmetry on y-axis is:

$x^{2}=4py$ (1)

With p the distance from the origin to the focus using p=6, the equation (1) of the parabola becomes:

$x^{2}=4(6)y=24y$ (2)

Note that the point B is on the parabola, so this point should satisfy the parabola equation (2) that allow us to use the value x=4.5 to find the y value associated to it, that it is the depth (h) of the reflector:

$(4.5)^{2}=24y$ , solving for y