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Juliette [100K]
3 years ago
6

A piece of amber is charged by rubbing with a piece of fur. If the net excess charge on the fur is +8.0 nC (+8.0 10-9 C), how ma

ny electrons were added to the amber?
Physics
1 answer:
Ann [662]3 years ago
6 0

Answer:

Number of electron on the fur will be 5\times 10^{10}electron

Explanation:

We have given net charge on the fur q=8nC=8\times 10^{-9}C

Charge on one electron e=1.6\times 10^{-19}C

Let there are n number of electrons

So ne=8\times 10^{-9}

n\times 1.6\times 10^{-19}=8\times 10^{-9}

n=5\times 10^{10}electron

So number of electron on the fur will be 5\times 10^{10}electron

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True or False If the mass of the object increases, then the potential energy of the object decreases.​
Tamiku [17]
False- the potential energy is force*distance and force is mass*acceleration so if there’s more mass, there’s more force, so there’s more potential energy
Hope that helps :)
5 0
3 years ago
In an attempt to reduce our dependence on non–renewable resources, and cut down on the harm to the environment, we could burn __
valentinak56 [21]

In an attempt to reduce our dependence on non-renewable resources, and cut down on the harm to the environment, we could burn biomass to produce electricity.

7 0
3 years ago
A 35.0-g object connected to a spring with a force constant of 40.0 N/m oscillates with an amplitude of 4.00 cm on a frictionles
slamgirl [31]

Answer:

(a) The total energy of the spring system is 0.032 J

(b) The speed of the object when its position is 1.20 cm is approximately 1.28996 m/s

(c) The kinetic energy when its position is 2.50 cm is 0.0195 J

Explanation:

The given parameters are;

The mass of the object connected to the spring, m = 35.0 g = 0.00

The force constant, k = 40.0 N/m

The amplitude of the oscillation, a = 4.00 cm = 0.04 m

Therefore, we have

(a) The total energy of the spring system, E given as follows;

E = PE + KE = 1/2·m·v² + 1/2·k·x²

Where;

v = The velocity of the spring

x = The extension of the spring

When the spring is completely extended, x = a, and v = 0, therefore;

The total energy of the spring system, E = 1/2 × k × a² = 1/2 × 40.0 N/m × (0.04 m)² = 0.032 J

(b) At x = 1.20 cm = 0.012 m, we have;

E = 1/2·m·v² + 1/2·k·x²

0.032 = 1/2 × 0.035  × v² + 1/2 ×  40 × 0.012²

0.032 - 1/2 ×  40 × 0.012² = 1/2 × 0.035  × v²

0.02912 = 1/2 × 0.035  × v²

1/2 × 0.035  × v² = 0.02912

v² = 0.02912/(1/2 × 0.035) = 1.664

v = √1.664 ≈ 1.28996

The speed of the object when its position is 1.20 cm,  v ≈ 1.28996 m/s

(c) When its position is 2.50 cm = 0.025 m, we have;

E = PE + KE

0.032 = 1/2 ×  40 × 0.025² + KE

KE = 0.032 - 1/2 ×  40 × 0.025² = 0.0195

The kinetic energy when its position is 2.50 cm = 0.0195 J.

4 0
3 years ago
A steel aircraft carrier is 370 m long when moving through the icy North Atlantic at a temperature of 2.0 °C. By how much does t
34kurt

Answer:

The carrier lengthen is 0.08436 m.

Explanation:

Given that,

Length = 370 m

Initial temperature = 2.0°C

Final temperature = 21°C

We need to calculate the change temperature

Using formula of change of temperature

\Delta T=T_{f}-T_{i}

\Delta T=21-2.0

\Delta T=19^{\circ}C

We need to calculate the carrier lengthen

Using formula of length

\Delta L=\alpha_{steel}\times L_{0}\times\Delta T

Put the value into the formula

\Delta L=1.2\times10^{-5}\times370\times19

\Delta L=0.08436\ m

Hence, The carrier lengthen is 0.08436 m.

8 0
3 years ago
The p wave on an electrocardiogram represents __________.
Harrizon [31]

It represents the depolarization of the atria.

<u>Explanation:</u>

The P wave speaks to the depolarization of the left and right chamber and furthermore relates to atrial compression. Carefully, the atria contract a brief moment after the P wave starts. Since it is so little, atrial repolarization is typically not unmistakable on ECG.

In an ordinary ECG, there's three particular waves. The primary wave is the P wave, which speaks to the depolarization of the atria. This happens directly before the atria agreement and drive blood into the ventricles. The following wave is known as the QRS wave.

3 0
3 years ago
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